For given problem:
Put midpoint of ellipse, (0,0) at epicenter of bridge at
ground level.
Specified length of vertical major axis = 70=2a
a=35
a^2=1225
Equation of ellipse:
x^2/b^2+y^2=1
plug in coordinates of given point on ellipse(25, 10)
25^2/b^2 + 10^2/a^2 = 1
625/b^2 + 100/1225=1
625/b^2 = 1 - 100/ 1225 = .918
b^2 = 625/.918 ≈ 681
b ≈ 26.09
length of minor axis = 2b = 2(26.09) ≈ 52.16 ft
Span of bridge ≈ 52.16 ft
<span>93-3=90
I hope this helps;)</span>
Answer:
Step-by-step explanation:I don't say you have to mark my ans as brainliest but if you think it has really helped you please don't forget to thank me....
Ok so the area of the frame is 18*12 = 216cm^2
Let’s suppose the width of the frame is x
The total area (painting and frame) is (2x+18)(2x+12) and this is equal to 432
4x^2 + 60x + 216 = 432
4x^2 + 60x - 216 = 0
x^2 + 15x - 54 = 0
(x+18)(x-3) = 0
Therefore x = {-18,3}
Since width of the frame has to be positive, the width has to be 3cm