Select the correct answer.
1 answer:
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We can write the system in the following form:
![\left[\begin{array}{cccc}5&-4&4&2\end{array}\right] \left[\begin{array}{c}x_1\\x_2\\x_3\\x_4\end{array}\right] =b](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D5%26-4%264%262%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx_1%5C%5Cx_2%5C%5Cx_3%5C%5Cx_4%5Cend%7Barray%7D%5Cright%5D%20%20%3Db)
The above system is equivalent to the following equation:
Of course, the above system has solution for any values of b since there is one equation and four variable, there is infinite number of solution each time.
The above system is equivalent to the following equation:
Of course, the above system has solution for any values of b since there is one equation and four variable, there is infinite number of solution each time.
Answer:
- a=1
- b=1
- c=-4
- x = (-1 ±√17)/2
Step-by-step explanation:
The coefficient of x^2 is "a". That is 1.
The coefficient of x is "b". That is 1.
The constant term is "c". That is -4.
The values of a, b, and c are 1, 1, and -4, respectively.
_____
The solution is ...
x = (-b ±√(b^2-4ac))/(2a)
Filling in the values of a, b, and c, this is ...
x = (-1 ±√(1^2 -4·1·(-4)))/(2·1)
x = (-1 ±√17)/2
