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11111nata11111 [884]
3 years ago
6

Needdddd help pls ill mark brainlist​

Mathematics
1 answer:
Ilya [14]3 years ago
4 0

Step-by-step explanation:

correct answer 2) y> 3x+2

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4 +y = 12. Substitute 8 for x.
Alexeev081 [22]

Answer:

where should I substitute 8 for x? if its like this 4(8)+y=12 than its y=-20

Step-by-step explanation:

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3 years ago
Will correctly calculated 45 ÷ 6 as 7.5. How can he find 4,500 ÷ 6 without dividing?
Anastasy [175]
Add the zeros on to 7.5 to which you would move the decimal and it should be like this 750.0 or 750
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Which expressions are equivalent to 16x^2- 36
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Please help me with the answer
liraira [26]

Answer:

-18

Step-by-step explanation:

-15+6=-9

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1 year ago
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Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
2 years ago
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