4. Analyze What does the poet express about the world in the final stanza

English

1 answer:

andrew-mc [135]3 years ago

7 0

This question seems to be incomplete. However, there´s enough information to find the right answer.

Answer:

The overall message of the poem is that freedom and safety are not only potentially temporary ("here we are free for a while"), but also everyone´s responsibility, whether we are directly affected or not.

Explanation:

In "Elsewhere," by Derek Walcott, the Caribbean poet reflects on the oppression, cruelty, and injustice happening in many places around the world that are ignored by those not affected by them. In the final stanza, he states that the "darker crime", meaning what´s even worst than those crimes, is the lack of action by those who could act against such injustices. According to him, showing concern but doing nothing about it is making "a career of conscience."

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Stainless steel rod has a gap of 0.0371 mm between its end and a rigid wall. The modulus of elasticity E = 210 GPa. The coeffici

alexgriva [62]

Answer:

The value of stress in the rod is 220.9 MPa

Explanation:

As the data is not complete, a similar question is found online and the missing data is used from that question. Similar question is attached herewith.

From the given data

The allowed total strain is given as $\delta_a=0.0371 mm$

The length of the rod is missing in this data which in the additional data is l=290 mm

The Modulus of Elasticity is given as E=210 GPa

The coefficient of thermal expansion is given as α= 10 ×10⁻⁶ mm / mm⋅°C.

The initial temperature is room temperature which is given as T1=22C

The final temperature is given as T2=140 C

The strain due to stress is given as

$\delta_s=\dfrac{\sigma l}{E}$

$\delta_s=\dfrac{\sigma (0.290)}{210\times 10^9}\\\delta_s=1.38095\sigma \times 10^{-12}$

Now the thermal strain is given as

$\delta_c=l\alpha \Delta T\\\delta_c=0.290\times 10 \times 10^{-6}(T_2-T_1)\\\delta_c=0.290\times 10 \times 10^{-6}(140-22)\\\delta_c=0.0003422$

So now the equation of the allowed strain is given as

$\delta_a=\delta_s+\delta_c\\0.0371\times 10^{-3}=1.38095\sigma \times 10^{-12}+0.0003422\\\dfrac{1.38095}{10^{12}}\sigma+0.0003422=\frac{0.0371}{1000}\\\sigma=-\dfrac{10^{12}\times \:0.0003051}{1.38095}\\\sigma=-220934863.68 Pa\\\sigma=-220.9 MPa$