<img src="https://tex.z-dn.net/?f=%5Cfrac%7B33%7D%7B4-%5Csqrt%7B5%5C%5C%7D%20%7D" id="TexFormula1" title="\frac{33}{4-\sqrt{5\\}

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Sidana [21]

3 years ago

}" alt="\frac{33}{4-\sqrt{5\\} }" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Dima020 [189]3 years ago

6 0

Answer:

$12+3\sqrt{5}$

Step-by-step explanation:

$(\frac{33}{4-\sqrt{5}})(\frac{4+\sqrt{5}}{4+\sqrt{5}})=\frac{132+33\sqrt{5}}{16-5}=\frac{11(12+3\sqrt{5})}{11}=12+3\sqrt{5}$

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