3 years ago

What is the approximate volume of the cylinder? Use 3.14 for π.

Mathematics

1 answer:

Artist 52 [7]3 years ago

4 0

c. 734.76 cm3 espero que te sirva :)

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in a class of 35 students 26 play football and play 20 long tennis, if 17 play above, many play neither.

Artyom0805 [142]

I hope this helps you

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3 years ago

What is the volume of this solid? Recall the formula V = Bh.

Viktor [21]

Answer:

280

Step-by-step explanation:

V=Bh

V=1/2(7x10)8 *it is a triangluar pyrmid so the base is a triangle*

V=1/2x70x8

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I’m not a true percent sure but I think it’s C

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Triss [41]

Answer:

$\lim_{n \to \infty} U_n =0$

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

Step(i):-

Given series is an alternating series

∑ $(-1)^{n} \frac{n^{2} }{n^{3}+3 }$

Let $U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }$

By using Leibnitz's rule

$U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }$

$U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}$

Uₙ-Uₙ₋₁ <0

Step(ii):-

$\lim_{n \to \infty} U_n = \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }$

$= \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }$

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$=\frac{1}{infinite }$

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∴ Given series is converges

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3 years ago

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Arisa [49]

Answer:

i think its 70 percent maybe

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