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3 years ago

261,256,251 find the 50th term

Mathematics

1 answer:

marshall27 [118]3 years ago

7 0

Answer:

$a_{50}=16$

Step-by-step explanation:

Given that,

An airthmetic sequence,

261,256,251

We need to find the 50th term.

We have,

first term, a = 261

common difference = 256-261 = -5

The nth term of the AP is given by :

$a_n=a+(n-1)d\\\\a_{50}=a+49d\\\\a_{50}=261+49(-5)\\\\a_{50}=16$

So, the 50th term of the sequence is 16.

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The line of best fit for a scatter plot is shown:

alex41 [277]

In the slope intercept form, b represents the y intercept.
y = mx +- b

Therefore, if the y intercept is at 6, the formula of the line will look like
<span>y=mx + 6
</span>
This eliminates the first two options,
$y = -6x + \frac{3}{4} 
$
and
$y=6x + \frac{3}{4}$

and leaves behind
$y= - \frac{3}{4} +6$
and
$y= \frac{3}{4} x+6$

Since the line you indicated is sloping downwards towards the lower right hand corner. It must have a negative slope.

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8 0

3 years ago

Given cos theta = - 2/5 and sin theta < 0, find the six trigonometric values. I need help with this

Lena [83]

Answer:

$\sin\,\theta =-\frac{\sqrt{21} }{5}$

$\tan\,\theta =\frac{\sqrt{21} }{2}$

$\sec\,\theta = \frac{-5}{2}$

$cosec\,\theta =\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{2}{\sqrt{21} }$

Step-by-step explanation:

$\cos\theta =\frac{-2}{5}$

As both $sin\,\theta$ ,

$\theta$ lies in the third quadrant.

In the third quadrant,

$\sin\theta$

$\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}$