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beks73 [17]
3 years ago
6

Jeff found 3 times as many seashells as his sister. Jeff found 39 seashells. How many seashells did his sister find? Write an eq

uation to represent the situation. Then solve the equation to answer the problem.
Mathematics
2 answers:
AysviL [449]3 years ago
5 0

Answer:

The answer is 117 39*3

Step-by-step explanation:

You just have to multiply 39*3 and then you will get 117

rjkz [21]3 years ago
3 0

Answer:

13

Step-by-step explanation:

U do 39 divided by 3 which equals 13

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The length of a rectangular backyard is 6 more than the width of the backyard. The perimeter of the backyard is 44 feet. What is
german

Answer:

112

Step-by-step explanation:

use substitution method:

make 2 equations:

44 = 2(l+w)      l=w+6

plug in l:

44 = 2 (w+6+w)

combine like terms:

44 = 2(2w+6)

distribute:

44 = 4w + 12

get 4w alone:

44 = 4w + 12

-12           -12

__________

32 = 4w

Divide to get w alone :

32 = 4w

__     __

4        4

w=8

plug w in:

l = w + 6

l = 8 + 6

get l alone on one side:

l = 14

plug l and w in an are equation:

14 x 8 = 112

7 0
4 years ago
A jar has 10 red marbles, 6 purple marbles, and 4 turquoise marbles. If you pull a red marble, you win nothing. If you pull a pu
Klio2033 [76]

Answer:

The expected value = -1.4 Dollars

Step-by-step explanation:

The number of red marbles = 10

The number of red purple = 6

The number of red turquoise = 4

The total number of marbles in the jar = 10 + 6 + 4 = 20 marbles

The prize won for pulling a red marble = 0

The prize won for pulling a purple marble = $2

The prize won for pulling a turquoise marble = $5

The probability of pulling a red marble = 10/20 = 1/2

The probability of pulling a purple marble = 6/20 = 3/10

The probability of pulling a turquoise marble = 4/20 = 1/5

Expected value, EV, probability is the foreseen or bankable future value value for a current investment. The expected value is found by finding the product of each outcome and the probability of occurrence of the outcome and then adding the values of the products together

To find the expected value, EV sum the prizes won multiplied by the probability of winning that prize and then subtract the cost of playing the game.

Therefore;

EV = 1/2×0 + 3/10×2 + 1/5 × 5 -3 = -1.4

The expected value = $(-1.4).

8 0
4 years ago
P
Ilya [14]
PSPSPSPSPSSPSPSPSPSPS
7 0
3 years ago
(X^-5y/y^3)^-1=<br><br> A)x^5/y^2<br> B)y^2/x^5<br> C)x^5 y^2<br> D)x^5 y^-3
Nezavi [6.7K]

\left(\frac{x^{-5}y}{y^3} \right)^{-1} \\ \\ =\frac{y^3}{x^{-5}y} \\ \\ =\frac{y^2}{x^{-5}} \\ \\ =\boxed{x^5 y^2}

3 0
2 years ago
Pls help will mark brainliest!!!!!!
Zina [86]
A. figure ABCD is similar to figure A'B'C'D'
4 0
3 years ago
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