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3 years ago

AYO where the E-gamers AT?

Mathematics

1 answer:

Maru [420]3 years ago

3 0

The egamer you are searching for is here sire

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HELP PLEASE?????????????????

Yakvenalex [24]

It’s d the students

8 0

2 years ago

A contractor charges $1,200 for 100 swat feet of roofing installed. At this rate, how much does it cost to have 1,000 square fee

Oliga [24]

Answer:

12000

Step-by-step explanation:

1200=100

x=1000

x=100*1200/100

3 0

3 years ago

Select all equations that could be used to find the measure of angle C, using the fact that the sum of all the angles in a trian

Semmy [17]

C = 180 - A - B

And

C = 180 - (A+B)

Hope I can help you :)
Brainliest answer :)) ?

4 0

3 years ago

Stephanie has 6 classes a day at school. Each class is 52 minutes long. She goes to school 5 days a week. How many minutes does

Yakvenalex [24]

Answer:

1560 minutes

Step-by-step explanation:

52minutes x 6 = 312minutes

312minutes x 5 = 1560 minutes

so that means, she spends 1560 minutes in class

5 0

3 years ago

Read 2 more answers

Assume the sample variances to be continuous measurements. Find the probability that a random sample of 25observations, from a n

konstantin123 [22]

Answer:

a) $P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502$

b) $P(13.848$ Step-by-step explanation:

Previous concepts

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

For this case we assume that the sample variance is given by $S^2$ and we select a random sample of size n from a normal population with a population variance $\sigma^2$ . And we define the following statistic:

$T = \frac{(n-1) S^2}{\sigma^2}$

And the distribution for this statistic is $T \sim \chi^2_{n-1}$

For this case we know that n =25 and $\sigma^2 = 6$ so then our statistic would be given by:

$\chi^2 = \frac{(n-1)S^2}{\sigma^2}=\frac{24 S^2}{6}= 4S^2$

With 25-1 =24 degrees of freedom.

Solution to the problem

Part a

For this case we want this probability:

$P(S^2 > 9.1)$

And we can multiply the inequality by 4 on both sides and we got:

$P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502$

And we can use the following excel code to find it: "=1-CHISQ.DIST(36.4,24,TRUE)"

Part b

For this case we want this probability:

$P(3.462 < S^2$

If we multiply the inequality by 4 on all the terms we got:

$P(3.462*4 < 4S^2 < 4*10.745)= P(13.848< \chi^2$ And we can find this probability like this: $P(13.848$ And we use the following code to find the answer in excel: "=CHISQ.DIST(42.98,24,TRUE)-CHISQ.DIST(13.848,24,TRUE)"

8 0

2 years ago