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Leya [2.2K]
3 years ago
7

AYO where the E-gamers AT?

Mathematics
1 answer:
Maru [420]3 years ago
3 0
The egamer you are searching for is here sire
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Based on the graph, what is the initial value of the linear relationship? (4 points)
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the answer is 5 hope this could help

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y=x+3

Step-by-step explanation:

y=mx+b

where m is the slope and b is the y-intercept so

y=1x+3

simplified

y=x+3

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Triangle KLM has vertices K(3, −5) , L(6, −5) , and M(2, −9) .
Leno4ka [110]

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The answer is below. Sorry that this is late.

Step-by-step explanation:

Hope this helps!

4 0
2 years ago
Which three lengths could be the lengths of the sides of a triangle?
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9, 15, 22.

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3 0
3 years ago
Read 2 more answers
Suppose a random sample of 100 observations from a binomial population gives a value of pˆ = .63 and you wish to test the null h
irakobra [83]

Answer:

We conclude that the population proportion is equal to 0.70.

Step-by-step explanation:

We are given that a random sample of 100 observations from a binomial population gives a value of pˆ = 0.63 and you wish to test the null hypothesis that the population parameter p is equal to 0.70 against the alternative hypothesis that p is less than 0.70.

Let p = <u><em>population proportion.</em></u>

(1) The intuition tells us that the population parameter p may be less than 0.70 as the sample proportion comes out to be less than 0.70 and also the sample is large enough.

(2) So, Null Hypothesis, H_0 : p = 0.70      {means that the population proportion is equal to 0.70}

Alternate Hypothesis, H_A : p < 0.70      {means that the population proportion is less than 0.70}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                           T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion = 0.63

            n = sample of observations = 100

So, <u><em>the test statistics</em></u>  =  \frac{0.63-0.70}{\sqrt{\frac{0.70(1-0.70)}{100} } }

                                     =  -1.528

The value of z-test statistics is -1.528.

<u>Now at 0.05 level of significance, the z table gives a critical value of -1.645 for the left-tailed test.</u>

Since our test statistics is more than the critical value of z as -1.528 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the population proportion is equal to 0.70.

(c) The observed level of significance in part B is 0.05 on the basis of which we find our critical value of z.

4 0
3 years ago
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