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Sati [7]
3 years ago
13

Solve the equation for the letter L: A=LW

Mathematics
1 answer:
jarptica [38.1K]3 years ago
3 0
\frac{L}{A} =LW ⇒ Multiply both sides by A
\frac{LA}{A}=LWA ⇒ The terms 'A' on the LHS cancel each other
L=LWA ⇒ Divide both sides by 'L'
\frac{L}{L}= \frac{LWA}{L} ⇒ The terms 'L' on the LHS cancel each other to '1' and the terms 'L' on the RHS will also cancel each other
1= WA

The correct answer is the last option = none of the above
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3 years ago
(12, 9, 4) What is the area of the parallelogram shown below?
zavuch27 [327]

area of the parallelogram is: b x h

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7 0
3 years ago
2(vh)/k=r Solve equation for v in terms of all other variables involved
aivan3 [116]

The equation v in terms of other variables is v = kr/2h

<h3>What is the subject of an equation?</h3>

It is a variable which is expressed in terms of other variables involved in the formula.

Formulas are written so that a single variable, the subject of the formula is on the L.H.S. of the equation. Everything else goes on the right side of the equation. We evaluate the formula by substituting for the literal numbers on the right hand side.

2(vh) / k = r

by cross multiplication

2(vh) = kr

divide both sides by 2h

v = kr/2h

In conclusion, v in terms of other variables is  kr/2h

Learn more about subject of an equation: brainly.com/question/657646

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6 0
2 years ago
A study was conducted and two types of engines, A and B, were compared. Fifty experiments were performed using engine A and 75 u
USPshnik [31]

Answer:

a) -6 mpg.

b) 2.77 mpg

c) The 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results, in mpg, is (-8.77, -3.23).

Step-by-step explanation:

To solve this question, we need to understand the central limit theorem, and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Gas mileage A: Mean 36, standard deviation 6, sample of 50:

So

\mu_A = 36, s_A = \frac{6}{\sqrt{50}} = 0.8485

Gas mileage B: Mean 42, standard deviation 8, sample of 50:

So

\mu_B = 42, s_B = \frac{8}{\sqrt{50}} = 1.1314

Distribution of the difference:

Mean:

\mu = \mu_A - \mu_B = 36 - 42 = -6

Standard error:

s = \sqrt{s_A^2+s_B^2} = \sqrt{0.8485^2+1.1314^2} = 1.4142

A. Find the point estimate.

This is the difference of means, that is, -6 mpg.

B. Find the margin of error

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = zs = 1.96*1.4142 = 2.77

The margin of error is of 2.77 mpg

C. Construct the 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results(5 pts)

The lower end of the interval is the sample mean subtracted by M. So it is -6 - 2.77 = -8.77 mpg

The upper end of the interval is the sample mean added to M. So it is -6 + 2.77 = -3.23 mpg

The 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results, in mpg, is (-8.77, -3.23).

8 0
3 years ago
Annie has $18.00 to spend at the grocery store. She is going to buy bags of nuts that cost $5.70 each and one box of cookies tha
Tcecarenko [31]

Answer: She can buy up to 2 bags of nuts

Step-by-step explanation:

Hi, to answer this question we have to write an inequality:

The product of the number of bags of nuts bought (n) and the price per bag (5.70); plus the price of one box of cookies (4.25) must be less or equal to Annie's money (18).

5.70n +4.25 ≤18

Solving for x:

5.70n ≤18 -4.25

5.70n ≤13.75

n ≤13.75/5.70

n ≤2.41  

n ≤2 (rounded)

She can buy up to 2 bags of nuts

8 0
3 years ago
Read 2 more answers
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