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3 years ago

14

Para reformar la cocina de su caja Berta compro la semana pasada 2 cajas de plaquetas para el suelo y 4 de azulejos para la pare

d por 200 €. Hoy la comprado 2 cajas más de plaquetas y otras 2 de azulejos per 130 € Cuanto cuesta la caja de plaquetas y la de azulejos

1 answer:

Anvisha [2.4K]3 years ago

6 0

Answer:

Caja de plaquetas = x = 30 €

Caja de azulejos = y = 35 €

Step-by-step explanation:

Deje que el costo de

Caja de plaquetas = x

Cuadro de mosaico = y

Por Berta

Para reformar su cocina, Berta compró la semana pasada 2 cajas de baldosas de plaquetas para el suelo y 4 cajas de baldosas para la pared por 200 €.

2x + 4y = 200 ...... Ecuación 1

Hoy

Hoy compré 2 cajas más de plaquetas y otras 2 de tejas por 130 €.

2x + 2y = 130 ..... Ecuación 2

Resolvemos usando el método de Eliminación

2x + 4y = 200 ...... Ecuación 1

2x + 2y = 130 ..... Ecuación 2

Restar la ecuación 2 de 1

2 años = 70

y = 70/2

y = 35 €

Resolviendo para x

2x + 4y = 200 ...... Ecuación 1.

2x + 4 × 35 = 200

2x + 140 = 200

2x = 200 - 140

2x = 60

x = 60/2

x = 30 €

el costo de

Caja de plaquetas = x = 30 €

Caja de azulejos = y = 35 €

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3 years ago

In ΔQRS, s = 2.3 inches, ∠S=51° and ∠Q=44°. Find the area of ΔQRS, to the nearest 10th of an square inch.

postnew [5]

Answer:

Area of ΔQRS = 2.3 square inches

Step-by-step explanation:

From the given information,

<S + <Q + <R = $180^{o}$

51 + 44 + <R = $180^{o}$

95 + <R = $180^{o}$

<R = $180^{o}$ - 95

= $85^{o}$

<R = $85^{o}$

Applying the Sine rule, we have;

$\frac{q}{SinQ}$ = $\frac{r}{SinR}$ = $\frac{s}{SinS}$

Using $\frac{r}{SinR}$ = $\frac{s}{SinS}$

$\frac{r}{Sin 85}$ = $\frac{2.3}{Sin51}$

r = $\frac{2.3*Sin85}{sin51}$

= 2.9483

r = 2.9 inches

Also, $\frac{q}{SinQ}$ = $\frac{s}{SinS}$

$\frac{q}{Sin44}$ = $\frac{2.3}{Sin51}$

q = $\frac{2.3*Sin44}{Sin51}$

= 2.0559

q = 2.0 inches

From Herons formula,

Area of a triangle = $\sqrt{s(s-q)(s-r)(s-s)}$

s = $\frac{2.3 + 2.0 + 2.9}{2}$

= 3.6

Area of ΔQRS = $\sqrt{3.6(3.6-2.0(3.6-2.9)(3.6-2.3)}$

= 2.2895

Area of ΔQRS = 2.3 square inches

8 0

2 years ago

Read 2 more answers

Solve for x. Show your work.<br><br> 1/2x - 1/4 = 3/5x + 2

Damm [24]

<h3>Answer:</h3>

$x = - \frac{45}{2}$

<h3>Step-by-step explanation:</h3>

$\frac{1}{2} x - \frac{1}{4} = \frac{3}{5} x + 2$

$20( \frac{1}{2} x - \frac{1}{4} ) = 20( \frac{3}{5} x + 2)$

$20 \times \frac{1}{2} x - 20 \times \frac{1}{4} = 20( \frac{3}{5} x + 2)$

$10x - 20 \times \frac{1}{4} = 20 \times \frac{3}{5} x + 20 \times 2$

$10x - 5 = 20 \times \frac{3}{5} x + 20 \times 2$

$10x - 5 = 4 \times 3x + 20 \times 2$

$10x - 5 = 4 \times 3x + 40$

$10x - 5 - 12x = 40$

$10x - 12x = 40 + 5$

$- 2x = 40 - 5$

$- 2x = 45$

$x = - \frac{45}{2}$

4 0

3 years ago

Read 2 more answers