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kogti [31]
3 years ago
9

A geologist is passing through a canyon that is known for frequent flooding. He comes across a tall rock that is in the middle o

f the flow of the floodwater. The geologist can tell that the rock has softer minerals in the middle than at its sides. If the floodwater continues to rise, how will it affect the rock?
A)It will erode the rock from the sides, resulting in a mushroom shape.

B)It will deposit sediments on the rock and increase the size of its base.

C)It will erode the middle of the rock more than the outer edges.

D)It will erode the base of the rock until it breaks apart and the rock tips over.
Geography
2 answers:
m_a_m_a [10]3 years ago
4 0
C ..............................

noname [10]3 years ago
4 0

Answer:

the anser is C am possetive i took the test.

Explanation:

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4 years ago
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Answer:

M(29, -12)

Explanation:

Given:

H(4\frac{1}{2}, -3\frac{1}{4}), X(2\frac{3}{4}, -2\frac{3}{4})

Required:

Coordinates of the Midpoint of HX

Solution:

Midpoint (M) of HX, for H(4\frac{1}{2}, -3\frac{1}{4}), X(2\frac{3}{4}, -2\frac{3}{4}) is given as

M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}).

Let H(4\frac{1}{2}, -3\frac{1}{4}) = (x_1, y_1)

X(2\frac{3}{4}, -2\frac{3}{4}) = (x_2, y_2)

Thus:

M(\frac{4\frac{1}{2} + 2\frac{3}{4}}{2}, \frac{-3\frac{1}{4} + (-2\frac{3}{4})}{2})

Convert to improper fractions

M(\frac{\frac{9}{2} + \frac{11}{4}}{2}, \frac{-\frac{13}{4} + (-\frac{11}{4})}{2})

M(\frac{\frac{18 + 11}{2}}{2}, \frac{\frac{-13 - 11}{4}}{2})

M(\frac{\frac{29}{2}}{2}, \frac{\frac{-24}{4}}{2})

M(\frac{29}{2}*2, \frac{-24}{4}*2

M(29, -12)

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Answer:

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Explanation:

hope i helped

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