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3 years ago

What does it mean to evaluate an expression in 5th grade

Mathematics

1 answer:

MrRa [10]3 years ago

3 0

Answer:

Usually it means to solve it. Sometimes they give you values to substitute in for variables (letters) in the math sentence/equation/expression.

Does that make sense?

Step-by-step explanation:

You might be interested in

The number of peanuts in bags is normally distributed with a mean of 184.7 peanuts

ioda

Standard deviation = 3.3

The data point = 178

The mean = 184.7

<h2>Further Explanation</h2>

To calculate the Z-score of a bag containing 178 peanuts, we should use the formula to calculating a z-score.

The formula for calculating a Z-score is as follows

$z = \frac{data Point - Mean}{Standard Deviation}$

This also implies

$z = \frac{178 - 184.7}{3.3}$

$Z= -2.03$

therefore, the correct answer is -2.03

A z-score determine the number of standard deviation from the mean a data point is.

some important factors about z-score include:

if it is a positive z-score, it indicates the data point is above average
if it is a negative Z-score, it indicates the data point is below average
if the z-score is close to 0, it then means the data point is close to average
if the z-score is above 3 or below -3, it is considered to be unusual

Learn More about Z-score at:

brainly.com/question/12876715

#learnwithbrainly

8 0

3 years ago

Evaluate -8y - 4x<br> When x = -6. y = 9

sergij07 [2.7K]

-8(9)= -72; -4(-6)= 24; -72+24= -48

6 0

3 years ago

Read 2 more answers

Remember to show work and explain. Use the math font.

MrMuchimi

Answer:

$\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}$

Step-by-step explanation:

$\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================$

$1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}$

$\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)$

$--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)$

$--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}$

6 0

3 years ago

An organic farm has been growing an heirloom variety of summer squash. A sample of the weights of 40 summer squash revealed that

natta225 [31]

Answer:

b. 0.0228

Step-by-step explanation:

We are given that

n=40

Mean, $\mu=402.7 g$

Standard deviation, $\sigma=8.8$ g

We have to find the probability hat the mean weight for a sample of 40 summer squash exceeds 405.5 grams.

$P(x>405.5)=P(\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}>\frac{405.5-402.7}{\frac{8.8}{\sqrt{40}}})$

$P(x>405.5)=P(Z>\frac{2.8}{\frac{8.8}{\sqrt{40}}})$

$P(x>405.5)=P(Z>2.01)$

$P(x>405.5)=1-P(Z\leq 2.01)$

$P(x>405.5)=1-0.977784$

$P(x>405.5)=0.022216$

Hence, option b is correct.

5 0

3 years ago

Write the formula to find the profit %, if selling price and cost price both are given.

jolli1 [7]

Answer:

$profit \: percent = \frac{sp - cp}{cp} \times 100 \: percent$

where,

SP=Selling price

CP=Cost price

<h3>For example:</h3>

Given,

Selling price(SP)= 1000

Cost price(CP)=800

Now,

$profit \: percent = \frac{sp - cp}{cp} \times 100 \: percent \\ = \frac{1000 - 800}{800} \times 100 \\ = \frac{200}{800} \times 100 \\ = 25 \: percent$

Hope this helps...

Good luck on your assignment..

5 0

3 years ago