Hello,
Assume Ax+By+Cz+D=0 the plane 's equation.
p=(0,0,0)==>A*0+B*0+C*0+D=0==>D=0
q=(0,1,0)==>A*0+B*1+C*0+0=0==>B=0
r=(1,2,3)==>A*1+0*2+C*3+0=0==>A=-3C
Let C=1==>A=-3
An equation of the plane is -3x+z=0
These two lines have the same rate of change
Start with the distance equation D=RT, then plug in numbers
194=R x 4.2, so all we have to do is divide 194 by 4.2.
Answer: 46.19 kph
The answer is 7/9.Hope it helps
The answer would be $119.10
174.13-90.50=83.63
83.63+35.47=119.1
