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Nezavi [6.7K]
2 years ago
9

Plz HELP!!

Mathematics
1 answer:
Juli2301 [7.4K]2 years ago
8 0

Answer:

1st, 2nd, and 4th

Step-by-step explanation:

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A certain brand of automobile tire has a mean life span of 35,000 miles, with a standard deviation of 2250 miles. Assume the lif
yawa3891 [41]

Answer:

Step-by-step explanation:

From the information given:

mean life span of a brand of automobile = 35,000

standard deviation of a brand of automobile = 2250 miles.

the z-score that corresponds to each life span are as follows.

the standard z- score formula is:

z = \dfrac{x - \mu}{\sigma}

For x = 34000

z = \dfrac{34000 - 35000}{2250}

z = \dfrac{-1000}{2250}

z = −0.4444

For x = 37000

z = \dfrac{37000 - 35000}{2250}

z = \dfrac{2000}{2250}

z = 0.8889

For x = 3000

z = \dfrac{30000 - 35000}{2250}

z = \dfrac{-5000}{2250}

z = -2.222

From the above z- score that corresponds to their life span; it is glaring  that the tire with the life span 30,000 miles has an unusually short life span.

For x = 30,500

z = \dfrac{30500 - 35000}{2250}

z = \dfrac{-4500}{2250}

z = -2

P(z) = P(-2)

Using excel function (=NORMDIST -2)

P(z) = 0.022750132

P(z) = 2.28th percentile

For x =  37250

z = \dfrac{37250 - 35000}{2250}

z = \dfrac{2250}{2250}

z = 1

Using excel function (=NORMDIST 1)

P(z) = 0.841344746

P(z) = 84.14th percentile

For x = 35000

z = \dfrac{35000- 35000}{2250}

z = \dfrac{0}{2250}

z = 0

Using excel function (=NORMDIST 0)

P(z) = 0.5

P(z) = 50th percentile

6 0
3 years ago
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