So,
123/20 is over 1. The denominator is 20, so what I would do is find out how many <em>whole </em>20's would fit in 123.
The result is that 6 20's would fit in 123 with 3 left over.
The answer is six and three-twentieths (6 3/20). It's already in simplest form.
Answer:
-4i = 4(cos 270 +i sin 270)
Step-by-step explanation:
We have a+ib = r(cosθ+isinθ)

Here a = 0 and b = -4
Substituting

-4i = 4(cos 270 +i sin 270)
Could it be A 116 and B 32 try that.
Formula used: cos(x) = 
Hope this helped!
~Just a girl in love with Shawn Mendes