Answer:
The first plane is moving at 295 mph and the second plane is moving at 355mph.
Step-by-step explanation:
In order to find the speed of each plane we first need to know the relative speed between them, since they are flying in oposite directions their relative speed is the sum of their individual speeds. In this case the speed of the first plane will be "x" and the second plane will be "y". So we have:
x = y - 60
relative speed = x + y = (y - 60) + y = 2*y - 60
We can now apply the formula for average speed in order to solve for "y", we have:
average speed = distance/time
average speed = 1625/2.5 = 650 mph
In this case the average speed is equal to their relative speed, so we have:
2*y - 60 = 650
2*y = 650 + 60
2*y = 710
y = 710/2 = 355 mph
We can now solve for "x", we have:
x = 355 - 60 = 295 mph
The first plane is moving at 295 mph and the second plane is moving at 355mph.
Solution:
As, we have to find , 
% of 20
If we have to Percent of a certain number it means , divide that number by 100 , for example x% means 
.
And if i am writing , x% of y it means , 
.
Answer:
the function is only increasing.
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
Since it is super-urgent, it is probably a test or quiz. I should not have answered the question. I will help by giving you an example. You will need to work it out using a calculator. This is the best I can do.
Well, you just divide 7056 by a guess number x.
Take the average of x and the quotient (result of division) and repeat again.
Example:
Find square-root of 700, with an initial guess of x=27.
The quotient is 25.92592592592592
Taking average of 25.92592592592592 and 27 gives 26.46296296296296.
Using new guess x=26.46296296296296 and repeat the same process, we get 26.45751367182438
Using the new guess x=26.45751367182438 and repeat the same process, we get 26.45751311064591 which is accurate to 13 places after the decimal.
If it is not clear, try finding square-root of 625 and the final answer should be 25 (exactly) after three or four repetitions.
Feel free to ask for more <em>explanations</em>.
