<h2>
Step-by-step explanation:</h2><h3>We firstly find the surface area of only one face of the cube:</h3><h3>Sa=a²</h3><h3>Sa=1.2²cm</h3><h3>Sa=1.44cm²</h3>
<h2>
Since the cube has 6 faces we multiply the surface area of one face(144cm²) with 6</h2>
Area(cube)=1.44cm²*6
=8.64cm²
<h2>
Same thing with the prism but we have to find the area of one of his triangle face and rectangle face</h2>
S(triangle)=5mm*4mm*1/2
=10mm²
S(rectangle)=7mm*5mm=35mm²
<h2>
The prism has 2 triangle faces and three rectangle faces so we multiply the area by those numbers and then we add those together to get the final area</h2>
S=10mm²*2+35mm²*3
S=20+105
S=125mm²
<h3><em>
Hope this helped..</em></h3><h3 /><h3><em>Hope this helped..
Brainliest pls..</em></h3>
Answer:
0
Step-by-step explanation:
∫∫8xydA
converting to polar coordinates, x = rcosθ and y = rsinθ and dA = rdrdθ.
So,
∫∫8xydA = ∫∫8(rcosθ)(rsinθ)rdrdθ = ∫∫8r²(cosθsinθ)rdrdθ = ∫∫8r³(cosθsinθ)drdθ
So we integrate r from 0 to 9 and θ from 0 to 2π.
∫∫8r³(cosθsinθ)drdθ = 8∫[∫r³dr](cosθsinθ)dθ
= 8∫[r⁴/4]₀⁹(cosθsinθ)dθ
= 8∫[9⁴/4 - 0⁴/4](cosθsinθ)dθ
= 8[6561/4]∫(cosθsinθ)dθ
= 13122∫(cosθsinθ)dθ
Since sin2θ = 2sinθcosθ, sinθcosθ = (sin2θ)/2
Substituting this we have
13122∫(cosθsinθ)dθ = 13122∫(1/2)(sin2θ)dθ
= 13122/2[-cos2θ]/2 from 0 to 2π
13122/2[-cos2θ]/2 = 13122/4[-cos2(2π) - cos2(0)]
= -13122/4[cos4π - cos(0)]
= -13122/4[1 - 1]
= -13122/4 × 0
= 0
2256 fist bumps. 47 fist bumps x 48 friends is 2256 fist bumps.
Answer: 2x+4+3(2x-1) is not equivalent to 8x-2. it is equivalent to 8x+1
Step by step solution:
Step 1 :
Equation at the end of step 1 :
(2x + 4) + 3 • (2x - 1)
Step 2 :
Final result :
8x + 1
Divide both sides by 2
a-c=2a
minus a fromboth sides
-c=a
