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sergejj [24]
3 years ago
9

Encuentra el perímetro. El largo de una pieza rectangular mide 6 cm menos que su ancho y el área es de 135 cm^2.

Mathematics
1 answer:
Archy [21]3 years ago
7 0

Answer:

No espanol

Step-by-step explanation:

No espanol only english si si?

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<span>9,    12,    19,    30,    ...</span>

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4 years ago
<img src="https://tex.z-dn.net/?f=%20Simplify%3A%20%5C%3A%2018%20%5Cdiv%2016%20%2B%20%5B8%20%5C%7B16%20%5Cdiv%20%2810%20-%20%5Co
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<h3><u>Simplify :</u></h3>

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - \overline{8 - 2 } \bigg)\bigg\} \bigg]}}}}

<u>Simplifying vinculum bar </u>

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - \overline{8 - 2 } \bigg)\bigg\} \bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - 6\bigg)\bigg\} \bigg]}}}}

<u>Simplifying parentheses brackets</u>

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div \bigg(10 - 6\bigg)\bigg\} \bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div 4\bigg\} \bigg]}}}}

<u>Simplifying curly brackets </u>

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{16 \div 4\bigg\} \bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{ \dfrac{16}{4} \bigg\} \bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \bigg\{ \cancel{\dfrac{16}{4}} \bigg\} \bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \times 4\bigg]}}}}

<u>Simplifying square brackets </u>

{:\implies{\small{\sf{18 \div 16 + \bigg[8 \times 4\bigg]}}}}

{:\implies{\small{\sf{18 \div 16 + 32}}}}

<u>According to BODMAS rule simplifying devision </u>

{:\implies{\small{\sf{18 \div 16 + 32}}}}

{:\implies{\small{\sf{ \dfrac{18}{16}  + 32}}}}

{:\implies{\small{\sf{{\cancel{\dfrac{18}{16}}  + 32}}}}}

{:\implies{\small{\sf{ 1.125 + 32}}}}

<u>Now, according to BODMAS rule simplifying addition</u>

{:\implies{\small{\sf{ 1.125 + 32}}}}

{:\implies{\small{\sf{33.125}}}}

{:\implies{\underline{\boxed{\pmb{\sf{Answer = 33.125}}}}}}

<u>∴ The answer is 33.125.</u>

<u>\underline{\rule{200pt}{2.5pt}}</u>

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