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adoni [48]
3 years ago
14

Which number is NOT in the solution set of x-8 < 14? A)17 B)19 C)21 D) 23

Mathematics
1 answer:
laiz [17]3 years ago
4 0

answer

d.2e

Step-by-step explanation:

x<22

a,b,c are all in except d.

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Rewrite 12/17 as a decimal number. Round to the nearest thousandth.
boyakko [2]
Let's rewrite the given fraction 12/17 to a  decimal number. Then Let's round to the nearest thousandth.
To do that, divide the numerator by the denominator.
=> 12 / 17
=> 0.7058
Le's round this to
=>0.706

8 0
3 years ago
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PLEASE HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP I ONLY WANT ANSWERS FROM PEOPLE WHO TRULY WANNA HELP
Sauron [17]

Answer:

I would assume $10 is the cost of the booth and 5 is how much she earns for each T-Shirt, so the equation would be 5x-10=65. Assume $65 is what she earned.

Therefore, the equation may be: (your question did not specify) 5x-10=65. so x is 15. Therefore, she sold 15 T-Shirts.

Correct Form:

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4 0
3 years ago
Please help me
galina1969 [7]

Answer:

Your answer is.....

In every big pieces there will be 3 * 1/3 pieces.

So total 12 of 1/3 pieces

Mark it as brainlist answer . follow me for more answer.

Step-by-step explanation:

7 0
3 years ago
What is the volume of a hemisphere with a radius of 2.1 m, rounded to the nearest tenth of a cubic meter?
Art [367]

Answer:

The volume of hemisphere is <u>19.4 cubic meter</u>.

Step-by-step explanation:

Given:

A hemisphere is with a radius of 2.1 m.

Now, to find the hemisphere volume with radius 2.1 m.

Radius\ (r) = 2.1 m.

So, we put formula to get the volume of hemisphere:

Volume=\frac{2}{3} \pi r^3\ \ \ \ \ (Taking\ the\ value\ of\ \pi =3.14)\\\\Volume=\frac{2}{3} \times 3.14\times 2.1^3\\\\Volume=\frac{2}{3} \times 3.14\times 9.26\\\\Volume=19.384\ cubic\ meter.

<u><em>Hence, the rounded to the nearest tenth of a cubic meter is 19.4 cubic meter.</em></u>

Therefore, the volume of hemisphere is 19.4 cubic meter.

3 0
3 years ago
Help me please help me
blsea [12.9K]
Check the picture below.

8 0
3 years ago
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