In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.
To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9
To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum). The probability is 11/36
Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.
P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9
<span>0.38709677419 is your answer</span>
For this case, we have by definition that, the median of a set of numbers is the average number in the set, after the numbers have been ordered from lowest to highest. If there is an even number in the set, the median is the average of the two middle numbers.
So, the given set is:
{4,5,5,6,10,11,12,13}
Since there are 8 numbers, the set is even. Then we find the average of the two numbers in the middle:

The median is 8
ANswer:
8
Answer:
Each burger will weight 0.6 pounds
Explanation:
Divide 4.8 by 8