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bagirrra123 [75]
2 years ago
14

X-3=14 use the opposite operation found in the equation.

Mathematics
2 answers:
tatuchka [14]2 years ago
8 0
The volume can be determine by subtracting volume of smaller cuboid from the volume of the bigger cuboid.
Thus, by removing smaller cuboid from the bigger, we can determine the volume of the resultant figure.
Thus, Option (b) is correct.
aleksandrvk [35]2 years ago
6 0

Step-by-step explanation:

x-3=14

x=14+3

x=17

verification

x(17)-3=14

17-3=14

14=14

You might be interested in
Point A has coordinates (3,4). After a translation 4 units left, a reflection across the x-axis, and a translation 2 units down,
jeka94

Answer:

The coordinates of the image of point A are (-1, -6)

Step-by-step explanation:

Let us revise the rule of translation to the left, down, and reflection across the x-axis

  • If the point (x, y) translated horizontally to the left by h units then its image is (x - h, y) ⇒ T (x, y) → (x - h, y)
  • If the point (x, y) translated vertically down by k units then its image is (x, y - k) ⇒ T (x, y) → (x, y - k)
  • If the point (x, y) reflected across the x-axis, then its image is (x, -y), the rule of reflection is rx-axis (x, y) → (x, -y)

∵ The coordinates of point A are (3, 4)

∵ It is translated 4 units left

∴ h = 4

→ By using the 1st rule above

∴ Its image is (3 - 4, 4)

∴ Its image is (-1, 4)

∵ Its is reflected across the x-axis

→ By using the 3rd rule above change the sign of its y-coordinate

∴ The new image is (-1, -4)

∵ It is translated 2 units down

∴ k = 2

→ By using the 2nd rule above

∴ The final image is (-1, -4 - 2)

∴ The final image is (-1, -6)

∴ The coordinates of the image of point A are (-1, -6).

6 0
3 years ago
. upper left chamber is enlarged, the risk of heart problems is increased. The paper "Left Atrial Size Increases with Body Mass
Sonbull [250]

Answer:

Part 1

(a) 0.28434

(b) 0.43441

(c) 29.9 mm

Part 2

(a) 0.97722

Step-by-step explanation:

There are two questions here. We'll break them into two.

Part 1.

This is a normal distribution problem healthy children having the size of their left atrial diameters normally distributed with

Mean = μ = 26.4 mm

Standard deviation = σ = 4.2 mm

a) proportion of healthy children have left atrial diameters less than 24 mm

P(x < 24)

We first normalize/standardize 24 mm

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (24 - 26.4)/4.2 = -0.57

The required probability

P(x < 24) = P(z < -0.57)

We'll use data from the normal probability table for these probabilities

P(x < 24) = P(z < -0.57) = 0.28434

b) proportion of healthy children have left atrial diameters between 25 and 30 mm

P(25 < x < 30)

We first normalize/standardize 25 mm and 30 mm

For 25 mm

z = (x - μ)/σ = (25 - 26.4)/4.2 = -0.33

For 30 mm

z = (x - μ)/σ = (30 - 26.4)/4.2 = 0.86

The required probability

P(25 < x < 30) = P(-0.33 < z < 0.86)

We'll use data from the normal probability table for these probabilities

P(25 < x < 30) = P(-0.33 < z < 0.86)

= P(z < 0.86) - P(z < -0.33)

= 0.80511 - 0.37070 = 0.43441

c) For healthy children, what is the value for which only about 20% have a larger left atrial diameter.

Let the value be x' and its z-score be z'

P(x > x') = P(z > z') = 20% = 0.20

P(z > z') = 1 - P(z ≤ z') = 0.20

P(z ≤ z') = 0.80

Using normal distribution tables

z' = 0.842

z' = (x' - μ)/σ

0.842 = (x' - 26.4)/4.2

x' = 29.9364 = 29.9 mm

Part 2

Population mean = μ = 65 mm

Population Standard deviation = σ = 5 mm

The central limit theory explains that the sampling distribution extracted from this distribution will approximate a normal distribution with

Sample mean = Population mean

¯x = μₓ = μ = 65 mm

Standard deviation of the distribution of sample means = σₓ = (σ/√n)

where n = Sample size = 100

σₓ = (5/√100) = 0.5 mm

So, probability that the sample mean distance ¯x for these 100 will be between 64 and 67 mm = P(64 < x < 67)

We first normalize/standardize 64 mm and 67 mm

For 64 mm

z = (x - μ)/σ = (64 - 65)/0.5 = -2.00

For 67 mm

z = (x - μ)/σ = (67 - 65)/0.5 = 4.00

The required probability

P(64 < x < 67) = P(-2.00 < z < 4.00)

We'll use data from the normal probability table for these probabilities

P(64 < x < 67) = P(-2.00 < z < 4.00)

= P(z < 4.00) - P(z < -2.00)

= 0.99997 - 0.02275 = 0.97722

Hope this Helps!!!

7 0
3 years ago
HURRY UP PLEASE I RLLY NEED THIS........ On a coordinate plane, the field is 1 unit up and 1 and one-half units to the left. The
nikitadnepr [17]

Answer:

(-1/2, 1)

Step-by-step explanation:

it's just coordinate planed

3 0
3 years ago
Read 2 more answers
In Juan's coin bank there are nickels (n),
alukav5142 [94]

Answer:

The answer is 8 quarters, 16 nickles, and 32 dimes

Step-by-step explanation:

  1. First, the equation would be (2/4d) x 5 +d x 10 +1/4d x 25= 600 (Don't put 6.00, that's dollars. We put 6 dollars into cents to make it easier.)
  2. Then we slowly start to solve: 10/4d + 10d + 25/4d = 600
  3. 10d+40d+25d/4 = 600 (Put all of that over 4, not first 25d)
  4. 75d= 600 x 4
  5. d=600 x 4/75 (same here put everything over 75)
  6. d=32
  7. So then n= 2 x 32/4 = 16
  8. Then n would be equal to : 1/4d= 1/4 x 32 = 8
  9. So your answer would be 8 quarters, 16 nickles, and 32 dimes.

Hope this helped :)

5 0
3 years ago
The price of an outdoor grill was marked up 15% over the previous year's model. If the previous year's model sold for $500, what
harkovskaia [24]
I thank the answer is 75 #I thank
8 0
3 years ago
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