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Anton [14]
3 years ago
11

The ones circled for my daughter plz❤️

Advanced Placement (AP)
1 answer:
Ronch [10]3 years ago
6 0
I can’t honestly see the picture
Nix
2 years ago
h o w
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Can displacement be in seconds
bogdanovich [222]
Displacement is a vector quantity, which means that we need to specify a magnitude and direction. So, unlike distance, displacement cares what direction the object is going when it moves between two points. So, in one dimension, displacement can be positive, negative, or zero
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What condition results in magma cooling and forming a “glassy” igneous rock?
Gennadij [26K]

Answer: C)  extremely rapid cooling

Explanation:

When magma goes through extremely rapid cooling and especially if it did not dissolve enough water into it, it could freeze to glass or the mineral crystals that will be formed will be so small, they will look like glass.

This is because the reactions that occur to create minerals are affected directly by temperature such that if the magma cools down extremely slowly, it will form very large crystals but extremely fast would result in small crystals.

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3 years ago
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Whats your zodiac sign also what your least favorite zodiac sign...
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I am an Aquarian and my least favourite zodiac is Leo...

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3 years ago
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Which of the following was one of the first Internet search engines
hammer [34]
I need to see the following.
4 0
3 years ago
I can’t figure this problem out
Natalka [10]

Answer:

Explanation:

Alright so the way to do this is to use properties of integrals to make our life easier.

So we have:

\int\limits^4_1 {(3f(x)+2)} \, dx

So lets break this up into two different integrals that represent the same area.

\int\limits^4_0 {f(x)} \, dx - \int\limits^1_0 {f(x)} \, dx = \int\limits^4_1 {f(x)} \, dx

Lets think about what is going on up there. The integral from four to zero gives us the area under the curve of f(x) from four to zero. If we subtract this from the integral from one to zero (the area under f from one to zero) we are left with the area under f from four to one! Hence:

\int\limits^4_1 {f(x)} \, dx

But since we have these values we can say that:

-3 - 2 = -5

Which means that \int\limits^4_1 {f(x)} \, dx = -5

So now we can evaluate \int\limits^4_1 {(3f(x)+2)} \, dx

Lets first break up our integrand into two integrals

\int\limits^4_1 {(3f(x)+2)} \, dx = 3\int\limits^4_1{f(x)} \, dx + 2\int\limits^4_1 {} \, dx

Now we can evaluate this:

We know that \int\limits^4_1 {f(x)} \, dx = -5

So:

3(-5)+2[x] where x is evaluated at 4 to 1 so

-15 + 2(3)

So we are left with -15 + 6 = -9

5 0
3 years ago
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