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3 years ago

Solve the system of equations by substitution. Write your solution as an ordered pair

Mathematics

2 answers:

oksano4ka [1.4K]3 years ago

6 0

Answer:

hello

Step-by-step explanation:

djh;vkajhkjbcbvusiwihalkjfbih

Elza [17]3 years ago

5 0

X+2(-2+11)=-2. plug in y
X-4+22=-2 distribute 2
+22 +22 Subtract +22
———————-
X-4=20
+4. +4. Add 4 to both sides

Answer is X=24

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Simplify 8 over the quantity of 2 plus 2i.

dexar [7]

$\dfrac{8}{2+2i}=\dfrac{8}{2(1+i)}=\dfrac{4}{1+i}=\dfrac{4}{1+i}\cdot\dfrac{1-i}{1-i}=\dfrac{4(1+i)}{1^2-i^2}\\\\=\dfrac{4(1+i)}{1-(-1)}=\dfrac{4(1+i)}{1+1}=\dfrac{4(1+i)}{2}=2(1+i)=2+2i\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\i=\sqrt{-1}\to i^2=-1$

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3 years ago

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yKpoI14uk [10]

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2 years ago

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rjkz [21]

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3 years ago

Write the quadratic equation whose roots are 3 and -1, and whose leading coefficient is 5.

Assoli18 [71]

Answer:

5x² - 10x - 15 = 0

Step-by-step explanation:

Given that the roots are x = 3 and x = - 1, then the factors are

(x - 3) and (x + 1) and the quadratic is the product of the factors, that is

f(x) = a(x - 3)(x + 1) ← a is a multiplier

Here a = 5, thus

f(x) = 5(x - 3)(x + 1) ← expand factors using FOIL

= 5(x² - 2x - 3) ← distribute parenthesis by 5

= 5x² - 10x - 15

Thus equation is

5x² - 10x - 15 = 0

6 0

4 years ago

The points (0, 1) and (-9, -9) fall on a particular line. What is its equation in slope-intercept form?

prohojiy [21]

The slope-intercept form:

$y=mx+b\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

m - slope

b - y-intercept → (0, b)

We have the points (-9, -9) and (0, 1) - y-intercept → b = 1.

Calculate the slope:

$m=\dfrac{1-(-9)}{0-(-9)}=\dfrac{10}{9}$

Answer: $y=\dfrac{10}{9}x+1$

4 0

3 years ago