First you have to make them both common denominators
the common denominator is 6 so then half of 6 is 3 so it is 3/6 and then 1/3 converted to a denominator of 6 is 2/6 so the answer is 3/6+2/6= 5/6
Let the first term, common difference and number of terms of an AP are a, d and n respectively.
Given that, 9th term of an AP, T9 = 0 [∵ nth term of an AP, Tn = a + (n-1)d]
⇒ a + (9-1)d = 0
⇒ a + 8d = 0 ⇒ a = -8d ...(i)
Now, its 19th term , T19 = a + (19-1)d
= - 8d + 18d [from Eq.(i)]
= 10d ...(ii)
and its 29th term, T29 = a+(29-1)d
= -8d + 28d [from Eq.(i)]
= 20d = 2 × T19
Hence, its 29th term is twice its 19th term
5th graders: 
x 96 = 16
4th graders: 
x 96 = 32
Remaining students: 96 - 16 - 32 = 48
2nd graders: 
x 48 = 12
Answer: 12 students
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here is a breakdown by grade level:
5th graders = 16, 4th graders = 32, 2nd graders = 12, all other grades = 36
Sorry !!!!!!!!!!!! But i can give u only 1.....
say, 10/3 u get 3.3333333..... , by rounding using place value u get 3.33 .
