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3 years ago

Hey can someone plz help me with this??? cute eyes

Mathematics

1 answer:

Leto [7]3 years ago

5 0

Answer:

A. 5

B. -5, 5

C. 5, 5

Step-by-step explanation:

A. |-6+(-1)| = 5

B. -6-(-1)=-6+1=-5

-1-(-6)=-1+6=5

C. |-6-(-1)|=|-6+1|=5

|-1-(-6)|=|-1+6|=5

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Use the following function rule to find f(-1).<br> f(x) = -11 + 8x<br> f(-1) =?

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Answer:

-19

Step-by-step explanation:

f(x) = -11 + 8x

f(-1) =-11 + 8(-1)

= -11 -8

= -19

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3 years ago

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One week Isabella bought 2 bags of apples 3 bags of oranges. Next week she bought 1 bag of apples and 2 bags of oranges what exp

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Use an area model to show the product of 8x2.23 write your answer in standard form answer

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Answer:

17.84

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2 years ago

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I need help with this problem

Arada [10]

Answer:

65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

That is let p and q be any two vectors and A be the angle between them

So, p·q=|p|*|q|*cosA

⇒ $cosA=\frac{u.v}{|u||v|}$

Given u=-8i-3j and v=-8i+8j

$|u|=\sqrt{(-8)^{2}+ (-3)^{2}} =8.544$

$|v|=\sqrt{(-8)^{2}+ (8)^{2}} =11.3137$

let A be angle before u and v

therefore, $cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}$

⇒ $A=arccos(\frac{40}{96.664} )=arccos(0.4138 )=65.56$

Therefore angle between u and v is 65.56°

5 0

2 years ago

webassign If a snowball melts so that its surface area decreases at a rate of 6 cm2/min, find the rate at which the diameter dec

drek231 [11]

Answer:

The answer is $\frac{3}{10\pi } cm/min$

Step-by-step explanation:

Assuming the snowball is a perfect sphere, then if A denotes the surface area and D the diameter then:

$A=4\pi r^{2} = 4\pi (\frac{D}{2} )^{2} =\pi D^{2}$

Differentiating wrt r we have:

$\frac{dA}{dD} =2\pi D$

We are told that $\frac{dA}{dt}= -6$ and we want to find $\frac{dD}{dt}$

By the chain rule we have:

$\frac{dA}{dD}=\frac{dA}{dt}.\frac{dt}{dD}=\frac{\frac{dA}{dt} }{\frac{dD}{dt} }$

∴ $2\pi D=-\frac{6}{\frac{dD}{dt} }$

∴ $\frac{dD}{dt}=-\frac{6}{2\pi D}$

When D=10 then

$\frac{dD}{dt} =-\frac{6}{10*2\pi } =-\frac{3}{10\pi }$

The sign (-) shows that the D is decreasing.

3 0

3 years ago

Hey can someone plz help me with this??? *cute eyes*

Hey can someone plz help me with this??? cute eyes