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3 years ago

Please solve this :)))))))

Mathematics

2 answers:

bonufazy [111]3 years ago

8 0

Answer:

21%

Step-by-step explanation:

look it up

ser-zykov [4K]3 years ago

6 0

It is 4 divided by 800 by the power of 2

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What is the slope intercept form of (3,3) (7,-1)

kow [346]

Slope intercept form follows this general equation...
$y=mx+b$
With this information you have posted, all you can do is find slope, your m. To calculate for slope, you need to use this following equation...
$m= \frac{y_2-y_1}{x_2-x_1}$
Then, you pick one of your coordinate pairs to be 1 and the other to be 2. I will choose the first coordinate pair as 1, so...
$m=\frac{-1-3}{7-3} =-1$
You plug in -1 into your slope formula...
$y=-1x+b$
Now, to find your y-intercept, or b, you must plug in one of your coordinate pairs. In that equation, you may plug in the values (3,3), so you'll have...
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3 years ago

How many quarts are in 12 liters

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7 0

3 years ago

Read 2 more answers

9 cos(sin¯¹(x)) = √81 – 81x²

Ira Lisetskai [31]

The equation 9cos(sin¯¹(x)) = √(81 – 81x²) is true since L.H.S = R.H.S

To answer the question, we need to know what an equation is

<h3>What is an equation?</h3>

An equation is a mathematical expression that show the relationship between two variables.

Given 9cos(sin¯¹(x)) = √(81 – 81x²), we need to show L.H.S = R.H.S

So, L.H.S = 9cos(sin¯¹(x))

= 9[√{1 - sin²(sin¯¹(x)}] (Since sin²y + cos²y = 1 ⇒ cosy = √[1 - sin²y])

9[√{1 - sin²(sin¯¹(x)}] = √9² × √{1 - sin²(sin¯¹(x)}]

= √[9² × {1 - sin²(sin¯¹(x)}]

= √[81 × {1 - sin²(sin¯¹(x)}]

= √[81 × {1 - x²}] (since sin²(sin¯¹(x) = [sin(sin¯¹(x)]² = x²)

= √(81 – 81x²)

= R.H.S

So, the equation 9cos(sin¯¹(x)) = √(81 – 81x²) is true since L.H.S = R.H.S

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6 0

2 years ago

Please Help!!

LuckyWell [14K]

the discriminant is:

D = (-1)^2 - 4*(-2)*6 = 49

We have a positive discriminant, which means that we have two real solutions.

<h3>How to find the discriminant?</h3>

For the general quadratic equation, the discriminant is:

a*x^2 + b*x + c = 0

The discriminant is:

D = b^2 - 4ac

In this case, the quadratic equation is:

6*x^2 - x - 2 = 0

Then we have:

a = 6, b = -1, c = -2

Replacing that in the discriminant equation:

D = (-1)^2 - 4*(-2)*6 = 49

We have a positive discriminant, which means that we have two real solutions.

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5 0

2 years ago

Can someone help me with these 5 math questions please? (40 points)

Aleksandr-060686 [28]

Answer

the answer for problem number one is -8

4 0

4 years ago