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zysi [14]
3 years ago
15

SOMEONE PLEASE HELP ME WITH THIS ILL GIVE YOU BRAINLY IF YOU GET IT RIGHT PLEASE ALSO EXPLAIN HOW YOU GOT THE ANSWER!!!

Biology
2 answers:
umka21 [38]3 years ago
5 0
The answer is “d” good luck.
anzhelika [568]3 years ago
4 0

Answer:

D it got this because im awesome

Explanation:

brainliest?????????????????????????????????????????????

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8 0
3 years ago
The domestic cat genome contains 2.9×109 base pairs. The length of linker DNA in mammals is 50 base pairs. Approximately how man
IgorLugansk [536]

Answer:

Number of nucleosomes in 2.9 * 10^9bp is equal to 1.47 * 10^7

Explanation:

For wounding one nucleosome, total length of DNA required is equal to 146 bp

The length of  linker DNA in mammals is equal to 50 bp

Thus , the total length of DNA that confides between two nucleosome is equal to the sum of wounding length of DNA and the linker length

= 146 + 50\\= 196bp

Thus, in 196bp length of DNA, the total number of nucleosomes is equal to 1

Thus, number of nucleosomes in 2.9 * 10^9bp is equal to

\frac{2.9* 10^9}{196} \\1.47 * 10^7

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3 years ago
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Sindrei [870]
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Please help !! I don’t know the answer !!
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8 0
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