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Juliette [100K]
3 years ago
15

Showing that (9, 1) is a solution of which inequality would justify shading inside the graph of the curve. x2 – y2 > 84 x ≥ 3

(y + 2)2 – 2 4(x – 4)2 – 16(y + 1)2 > 36 64(x – 8)2 + 12y2 < 144
Mathematics
2 answers:
serg [7]3 years ago
6 0

Answer: It's D 64(x-8)2 + 12y2 < 144 on Edge

Step-by-step explanation:

labwork [276]3 years ago
5 0

Answer:

d

Step-by-step explanation:

edg 2021

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What are the minimum and maximum values?<br> Y=10cos(5x)-1
Zepler [3.9K]
Look max or min value of 10 cosx will varry according to value of cosx and we know that 
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6 0
3 years ago
Would this be a combination or permutation? (probability) (i need to show work too)
Scilla [17]

Answer:

1.) Combination

2.) 126

Hope this helps!

Step-by-step explanation:

A permutation when the order of selection is a factor.

A combination when order is not a factor.

8 0
3 years ago
Read 2 more answers
PLZ HURRY
amm1812

Answer:

39.92

Step-by-step explanation:

10%=4.99

20%=9.98

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7 0
3 years ago
A bee flies at 10 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 18 ​minutes, and the
ololo11 [35]

Step by Step answer

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4 0
2 years ago
Complete the factorization of 3x ^ 2 - 10x + 8 3x^ 2 -10x+8=(x- Box x-4)
aniked [119]

Answer:

3x^2-10x+8=(x-x_1)(x-x_2)=(x-2)(x-\frac{4}{3})

Step-by-step explanation:

The general form of a quadratic polynomial is given by:

ax^2+bx+c    (1)

You have the following polynomial:

3x^2-10x+8    (2)

In order to complete the factorization you can use the quadratic formula, to obtain the roost of the polynomial. The quadratic formula is given by:

x_{1,2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}    (3)

By comparing the equation (1) with the equation (2) you obtain:

a = 3

b = -10

c = 8

Then, you replace these values in the equation (3):

x_{1,2}=\frac{-(-10)\pm \sqrt{(-10)^2-4(3)(8)}}{2(3)}\\\\x_{1,2}=\frac{10\pm2}{6}\\\\x_1=2\\\\x_2=\frac{4}{3}

Then, the factorization of the polynomial is:

3x^2-10x+8=(x-x_1)(x-x_2)=(x-2)(x-\frac{4}{3})

5 0
3 years ago
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