I will edit this if you edit your question..
Im confused. This is not a question..
Answer:
The answer would be C if I am correct
Explanation:
The reason being is because white collar crimes are non-violent and usually are finance related and involves business or government things, so money laundering would make sense, i hope this helps
Answer:
subset([],[]).
subset([X|L],[X|S]) :-
subset(L,S).
subset(L, [_|S]) :-
subset(L,S).
Success:
subset([1,3], [1,2,3]).
subset(X, [1,3,4]). % error handling to compare sets in a given order
Fail:
subset([2,1], [1,2,3]). % compares in a different order from the first.
Explanation:
The function "Subset" in the source code above accepts two sets, then checks if the first set is a subset of the second. The code returns true if the condition is met.
Procedure SumEvenOdd(stdin: array [0..100] of integer)
var
i, sum_even, sum_odd: integer;
begin
for i := 0 to 100 do begin
if stdin[i] < 0 then
break;
if stdin[i] mod 2 = 0 then //even number
sum_even := sum_even + stdin[i]
else
sum_odd := sum_odd + stdin[i];
ShowMessage('sum of even is ' + IntToStr(sum_even) + ' ' + 'sum of odd is' + IntToStr(sum_odd) ) ;
end;
end
There's definitely something wrong with your for loop. Try this:
for x in range(n):
You might want to check if all your print statements are correct. You might be missing just a period and it will be counted wrong.
