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Mkey [24]
3 years ago
12

Here to you!!!!!!!! now prove it

Mathematics
1 answer:
Andrew [12]3 years ago
7 0

Answer:

teenagers who watch TV =2

teenagers wearing glasses =5

hence probability =2/5=0.4

now you prove how ur answer is 0.5

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3 years ago
Please help me!!! 60 points 2 questions and show work!!!!!!!!
Grace [21]

1.\\\dfrac{9}{2}(8-x)+36=102-\dfrac{5}{2}(3x+24)\ \ \ \ |\text{multiply both sides by 2}\\\\\not2^1\cdot\dfrac{9}{\not2_1}(8-x)+2\cdot36=2\cdot102-\not2^2\cdot\dfrac{5}{\not2_1}(3x+24)\\\\9(8-x)+72=204-5(3x+24)\ \ \ \ |\text{use distributive property}\\\\(9)(8)+(9)(-x)+72=204+(-5)(3x)+(-5)(24)\\\\72-9x+72=204-15x-120\ \ \ \ |\text{use commutative and associative property}\\\\-9x+(72+72)=-15x+(204-120)\\\\-9x+144=-15x+84\ \ \ \ |\text{subtract 144 from both sides}

-9x=-15x-60\ \ \ \ |\text{add 15x to both sides}\\\\6x=-60\ \ \ \ |\text{divide both sides by 6}\\\\\boxed{x=-10}


2.\\-12x-0.4 > 0.2(36.5x+80)-55\ \ \ \ |\text{use distributive property}\\\\-12x-0.4 > (0.2)(36.5x)+(0.2)(80)-55\\\\-12x-0.4 > 7.3x+16-55\ \ \ \ |\text{use associative property}\\\\-12x-0.4 > 7.3x+(16-55)\\\\-12x-0.4 > 7.3x-39\ \ \ \ |\text{add 0.4 to both sides}\\\\-12x > 7.3x-38.6\ \ \ \ |\text{subtract 7.3x from both sides}\\\\-19.3x > -38.6\ \ \ \ \ |\text{change the signs}\\\\19.3x < 38.6\ \ \ \ |\text{divide both sides by 19.3}\\\\\boxed{x < 2}


4 0
4 years ago
Read 2 more answers
For the following​ distribution, decide whether you expect the​ mean, median, or mode to give the best representation of the cen
valentinak56 [21]

Answer:

The median because it is unaffected by outliers.

Step-by-step explanation:

While mean is one of the most well known and used central tendency measurements, it has some weaknesses. Mean will show inaccurate data if there are outliers that have a very huge/small value. Income is one of the things that can hugely vary among people. A billionaire can pull the data up and make the mean show result that higher than it should be. In this case, the median is better to show the data. The mode is used for nominal data, while income is ordinal.

5 0
3 years ago
6. Solve for x.<br> 10x - 4 = +(8x + 14)
Nuetrik [128]

Simplify brackets

10x - 4 = 8x + 14

Add 4 to both sides

10x = 8x + 14 + 4

Simplify 8x + 14 + 4 to 8x + 18

10x = 8x + 18

Subtract 8x from both sides

10x - 8x = 18

Simplify 10x - 8x to 2x

2x = 18

Divide both sides by 2

x = 18/2

Simplify 18/2 to 9

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3 0
3 years ago
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In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b
madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding (ax+by)^7 using Binomial expansion, we have that:

(ax+by)^7 =

(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7

= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> a^7 = 128

=> a = \sqrt[7]{128}\\ \\\\a = 2

For the second term:

a^6b = -224

b = \frac{-224}{a^6}

b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5

Therefore, a = 2, b = 3.5

5 0
3 years ago
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