The answer is 11abc^2 + 12a^2b + 18b^2c because:
14abc^2-3abc^2 is 11abc^2
12a^2b + 0 = 12a^2b
16b^2c +2b^2c = 18b^c
Answer:
C
Step-by-step explanation:
to find the zeros you look at what value you would fill in for x to make zero, so (x+3) would have a zero of -3 and (x-2) would have a zero of 2
I suppose that when you write "log^6" , you want to say log₆
Change of base formula:
loga b=logc b / logc a
log₆ 120=ln 120 / ln 6=2.67
Answer: log₆ 120=2.67
3/5 x 4 = 12/20
H = 12
Sorry if wrong
When you multiply two complex numbers given in polar form, the argument of the product is the sum of the arguments of the factors. Meanwhile, the modulus of the product is the product of the moduli of the factors.
In this case, you'd have

and the modulus would simply be

. Since

we would expect the final product to fall in the first quadrant.