Answer: -3 2/3x - 1
Step-by-step explanation:
-2/3x + 5(3/5 - 3/5x) - 12 / 6 * 2
First distribute
-2/3x + 3 - 3x - 12 / 6 * 2
Now divide 12 by 6
-2/3x + 3 - 3x -2 * 2
Now multiply -2 by 2
-2/3x + 3 - 3x - 4
Now subtract 3x from -2/3x
-3 2/3x + 3 - 4
Now subtract 4 from 3
-3 2/3x - 1
Start by decomposing the number inside the root into primes
Then group the terms into cubes if possible

rewrite the root
![\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B80%7D%3D%5Csqrt%5B3%5D%7B10%5Ccdot2%5E3%7D)
then cancel the terms that are cubes and bring them out of the root
Answer:
0.47 and 11.53
Step-by-step explanation:
h = 60t − 5t²
27 = 60t − 5t²
5t² − 60t + 27 = 0
Quadratic formula:
x = [ -b ± √(b² − 4ac) ] / 2a
t = [ -(-60) ± √((-60)² − 4(5)(27)) ] / 2(5)
t = (60 ± √3060) / 10
t = 0.47 or 11.53