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3 years ago

IG mutuals ??????? mine is magyaraceli

Mathematics

1 answer:

noname [10]3 years ago

4 0

Answer:

teczoneq:) im rlly awkward tho-

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Write this number in expanded form 73,489

mart [117]

the answer is 70,000+3,000+400+80+9

3 0

4 years ago

Granola costs $6.50 per pound. Assorted nuts cost $9 per pound. How many pounds of granola and nuts are needed to make 9 pounds

bezimeni [28]

Answer:

3.6 pounds of granola and 5.4 pounds of nuts

Step-by-step explanation:

Let the required granola be x pounds, then amount of nuts is 9 - x.

<u>The price of the mixture is as below equation:</u>

6.5x + 9(9 - x) = 8*9
6.5x + 81 - 9x = 72
81 - 2.5x = 72
2.5x = 81 - 72
2.5x = 9
x = 9/2.5
x = 3.6

<u>Find the amount of nuts:</u>

9 - 3.6 = 5.4

7 0

2 years ago

I need help with math

Nata [24]

Answer:

Question 13. I believe is C.

Step-by-step explanation:

take your area of the face you are given aka your 7 5/6 and multiply it by six since there are six faces.

You can convert the mixed number to an improper fraction

$7 \frac{5}{6}$ = denominator times the whole number ( 6x7)= then add the numerator (42+5)= $\frac{47}{6}$

Then multiply by six to get your answer

I'm not completely sure about question number fourteen so I am not answering it.

8 0

3 years ago

Here is an equation for a circle: (x-3)^2 + (y+10)^2 = 81.

saw5 [17]

Answer: 2.

Step-by-step explanation: Write the equation of the circle using h = 2, k = –1, and r = ... (x – 1). 2. + y. 2. = 4 is a circle with center (1, 0) and a radius of 2.

7 0

3 years ago

Give me an example of an irrational number that is greater than 10

Pavel [41]

To find:

An irrational number that is greater than 10.

Solution:

Irritation number: It cannot be expression in the form of $\dfrac{p}{q}$ , where, $q\neq 0, p,q$ are integers.

For example: $\sqrt{2}\sqrt{3},\pi, 1.263689...,etc.$ .

We know that square of 10 is 100. So, square root of any prime number is an example of an irrational number that is greater than 10.

First prime number after 100 is 101.

Required irrational number $=\sqrt{101}$

Therefore, $\sqrt{101}$ is an irrational number that is greater than 10.

5 0

4 years ago