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melisa1 [442]
3 years ago
14

I NEED HELP ! ill mark brainlist

Mathematics
1 answer:
Naya [18.7K]3 years ago
8 0

Answer:(x + 3)(x + 3)

Step-by-step explanation:

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NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t2+121t
Alenkasestr [34]

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by

h(t)=-4.9t^2+121t+283

The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:

h(t)=0\implies-4.9t^2+121t+283=0

Using the quadratic formula, the solution for our problem is

\begin{gathered} t=\frac{-(121)\pm\sqrt{(121)^2-4(-4.9)(283)}}{2(-4.9)} \\ =\frac{121\pm142.083778...}{9.8} \\ =\frac{121+142.083778...}{9.8} \\ =26.8452834694... \end{gathered}

The rocket splashes after 26.845 seconds.

The maximum of this function happens at the root of the derivative. Differentiating our function, we have

h^{\prime}(t)=-9.8t+121

The root is

-9.8t+121=0\implies t=\frac{121}{9.8}=12.347

Then, the maximum height is

h(12.347)=1029.99

1029.99 meters above sea level.

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1 year ago
PLEASE HELP ASAP! 30 points!
rusak2 [61]
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223,000 is the answer
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Answer:

148

Step-by-step explanation:

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