For left put 2 on each
On the box over 100 put 82, and put 82 in the box on the right
Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative

2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function

3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
Answer:
b. {(-1.5, 9.5), (1,7)}
Step-by-step explanation:
brainliest please? :)
1: You are looking to find the mps increase over a second
2: 45 m/s from 0 m/s in 10 secs that is 4.5 m/s per second
3: The acceleration is 4.5m/s
Answer:
2x + y = 7
x=7/2
y=7
Step-by-step explanation:
to find y itercept =0
to find x intercept=0