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3 years ago

Can someone help me pretty pls?

Mathematics

2 answers:

klio [65]3 years ago

4 0

I think it would be 25

Andrews [41]3 years ago

3 0

Answer:

it would be 27

Step-by-step explanation:

the inside of a right triangle is 180 degrees, so you add the right angle (90) and the 63 to get 153 and then subtract that from 180

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This is 7 th grade math please help me please

lapo4ka [179]

So all you what to do is find the base amount which means how much is one pound of candy then multiply that by 12 to get letter c and u would do the same to letter d but multiple the money

4 0

4 years ago

Help me please I need help on my quiz

Deffense [45]

Answer:

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8 0

3 years ago

Hello, i’m stuck on this question can anyone help me please here is a pic, i’m putting 17 points that’s the highest it lets me..

kykrilka [37]

Answer:

So we can try all answers with -10 we get -11/4 = -2.75. And that is less so it works. -7 wont work because -8/4 = -2 and its not less than its the same. So the higher you go it wont work. So that rules out -7, -5, and -1. For 0 you get -1/4 = 0.25 which also doesn't work.

<h2><u>Only 1 answer: A</u></h2>

8 0

4 years ago

Let X have the uniform distribution U(0, 2) and let the conditional distribution of Y , given that X = x, be U(0, x). Find the j

Elina [12.6K]

Answer:

$f(x,y) = \frac{1}{x} \frac{1}{2}= \frac{1}{2x} , 0\leq x \leq 2 , 0\leq y \leq x$

$E(Y|x) = \int_{x=y}^2 y \frac{1}{x} dx= y ln x \Big|_{x=y}^2 =y ln 2 -y ln y = y(1-lny) \$

Step-by-step explanation:

We have two random variables X and Y. $X \sim Unif(0,2)$ and given that X=x, Y has uniform distribution (0,x)

From the definition of the uniform distribution we have the densities for each random variable given by:

$f_X (x) =\frac{1}{2} , 0\leq x\leq 2$

$f_{Y|X} (y|x) = \frac{1}{x}, 0\leq y \leq x$

And on this case we can find the joint density with the following formula:

$f(x,y) = f_{Y|X}(y|x) f_X (x)$

And multiplying the densities we got this:

$f(x,y) = \frac{1}{x} \frac{1}{2}= \frac{1}{2x} , 0\leq x \leq 2 , 0\leq y \leq x$

Now with the joint density we can find the expected value E(Y|x) with the following formula:

$E(Y|x) = \int y f_{Y|X}(y|x)dx$

And replacing we got:

$E(Y|x) = \int_{x=y}^2 y \frac{1}{x} dx= y ln x \Big|_{x=y}^2 =y ln 2 -y ln y = y(1-lny) \$

5 0

3 years ago

A fish population in a lake decreases by 2% each year. What is the common ratio? (Write your answer as a decimal)

galina1969 [7]

Answer:

the common ratio is 0.98.

Step-by-step explanation:

A fish population in a lake decreases by 2% each year. We are asked to find the common ratio.

The decrease of population of fish 2% annually means the population becomes next year 100% - 2% = 98%

Therefore, the common ratio would be 98%. Upon converting 98 percent to a decimal we will get,

98% = $\frac{98}{100}=0.98$

Therefore, the common ratio or decay factor is 0.98.

8 0

3 years ago