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3 years ago

12

Please help me asap!!!

2 answers:

Vitek1552 [10]3 years ago

5 0

Girl I don’t know sorry good luck though

lesya692 [45]3 years ago

5 0

HI=37. it's a lot to explain

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Help, in geometry please?<br><br>Thank you!

Svet_ta [14]

1) Draw the triangles JKL and J'K'L' in a same coordinate system.

When I did that, I realize the if you translate the triangle JKL 1 unit left and then you reflects the image across the x-axys you get the you get the triangle J'K'L'.

So, select the boxes in that same order:

1) translation 1 unit left

2) reflection across the x - axis.

2) The answer ot the second question is line r.

That is called the line of reflection because if you reflect the figures through it you will have the same figure.

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3 years ago

What equation represents a line that is parallel to the line y=3-2x

GarryVolchara [31]

The line whose equation is

y = (any number) - 2x

is parallel to the line y = 3 - 2x , because they have the same slope.

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4 years ago

Which could be the first step in solving the equation represented by the model below?

vekshin1

Answer: A. Add 4 negative unit tiles to both sides.

Step-by-step explanation: Hope this helps

7 0

3 years ago

The number of leaves that fall off a tree n days after day 1 is given by the function f (n) = 3(2)".

densk [106]

Answer:

A. On the first day, 3 leaves fall.

B. D. The number of leaves that fall on a given day is 2 times the number of leaves that fell on the previous day.

Step-by-step explanation:

Given

$f(n) = 3(2)^n$

Solving (a) The meaning of 3.

3 represents the initial number of leaves (i.e. the first day) and this proved as follows.

On the first day, n = 0.

Substitute 0 for n in $f(n) = 3(2)^n$

$f(0) = 3(2)^0$

$f(0) = 3*1$

$f(0) = 3$

Solving (b) The meaning of 2.

2 represents the rate which leaves fall down.

In (a)

$f(0) = 3$

Take n = 1

Substitute 1 for n in $f(n) = 3(2)^n$

$f(1) = 3(2)^1$

$f(1) = 3*2$

$f(1) = 6$

When f(1) is divided by f(0), the result 2. So, the number of leaves doubles everyday

4 0

3 years ago

For which pair of functions is the vertex of k(x)7 units below the vertex of f(x)?

kvv77 [185]

Answer: Option C

$f(x) = x^2;\ k (x) = x ^ 2 -7$

Step-by-step explanation:

Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:

$k (x) = f (x) + b$

If $b> 0$ then the graph of k(x) will be the graph of f(x) displaced vertically b units down.

If $b> 0$ then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.

In this case we have

$f (x) = x ^ 2$

We know that this function has its vertex in point (0,0).

Then, to move its vertex 7 units down we apply the transformation:

$k (x) = f (x) - 7\\\\k (x) = x ^ 2 -7$ .

Then the function k(x) that will have its vertex 7 units below f(x) is

$k (x) = x ^ 2 -7$

3 0

3 years ago