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Marrrta [24]
2 years ago
8

46 + [3(2+5)] + 5} Simplify expression using order of operations

Mathematics
2 answers:
salantis [7]2 years ago
7 0

Answer:

72

Step-by-step explanation:

To solve 46 + {[3(2+5)]+5}, you would first do what is inside the () so that would be 2+5, then you would move outward multiplying 7 by 3 to get 21, then adding 5 to get 26. Then you would finally add 46 to get 72

ElenaW [278]2 years ago
3 0

uhhhh

Step-by-step explanation:

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The price of an item has been reduced by 70% the original price was $58 what’s the price of the item now ¿
Mamont248 [21]

Answer:$17.40  


Step-by-step explanation:

This is a very simple question. First since 70% is the amount of money removed, we do 100-70=30

30% is the price that remains. Change that into a fraction 30/100 and then multiply the original cost

30/100*58=17.4

The answer is $17.40  

6 0
3 years ago
Help Pls! It's for my Math 4! Scalar Multiplication!
prohojiy [21]

Answer:

Concept: Physics Qualitative Analysis.

  • Scalar values are constant and compared to vector values they do not have a direction or magnitude or a gradient representation.
  1. Lets get started by setting up the equation
  2. They want us to find 3U-2V
  3. Given U= <6,6> V=<6,-6>
  4. Now we plug in and solve!
  5. 3<6,6>- 2<6,-6>
  6. <18,18>-<12,-12>
  7. Subtract
  8. <18-12,18-(-12)>
  9. Hence that gives us a result of <6,30>
  10. Now with the skills you gained solve the rest!!!
8 0
3 years ago
Read 2 more answers
*PLEASE HURRY WILL GIVE BRAINLY* A company's profits (in dollars) are modeled by the function p(x) = —x^2+ 1100x - 300000, where
LekaFEV [45]
No, it’s not correct. The y-axis on the graph represents the profits p(x) so the minimum number of units produced should be when the a horizontal line at y = 590 first intersects the parabola drawn left to right, and not a vertical line at x = 590 because that represents the profit as 590 units are produced.
4 0
2 years ago
The random variable X has the following probability density function: fX(x) = ( xe−x , if x &gt; 0 0, otherwise. (a) Find the mo
dusya [7]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

Given value:

\to f_X (x) \ \ xe^{-x} \ , \ x>0

For point a:

Moment generating function of X=?

Using formula:

\to M(t) =E(e^{tx})= \int^{\infty}_{-\infty} \ e^{tx} f(x) \ dx

M(t) = \int^{\infty}_{-\infty} \ e^{tx}xe^{-x} \ dx = \int^{\infty}_{0} \ xe^{(t-1)x} \ dx

integrating the values by parts:

u = x \\\\dv = e^{(t-1)x}\\\\dx =dx \\\\v= \frac{e^{(t-1)x}}{t-1}\\\\M(t) =[\frac{e^{(t-1)x}}{t-1}]^{-\infty}_{0}  -\int^{\infty}_{0} \frac{e^{(t-1)x}}{t-1} \ dx\\\\  

        = \frac{1}{t-1} (0) - [\frac{e^{(t-1)x}}{(t-1)^2}]^{\infty}_{0}\\\\=\frac{1}{(t-1)^2}(0-1)\\\\=\frac{1}{(t-1)^2}\\\\

Therefore, the moment value generating by the function is =\frac{1}{(t-1)^2}

In point b:

E(X^n)=?

Using formula: E(X^n)= M^{n}_{X}(0)

form point (a):

\to M_{X}(t)=\frac{1}{(t-1)^2}

Differentiating the value with respect of t

M'_{X}(t)=\frac{-2}{(t-1)^3}

when t=0

M'_{X}(0)=\frac{-2}{(0-1)^3}= \frac{-2}{(-1)^3}= \frac{-2}{-1}=2\\\\M''_{X}(t)=\frac{(-2)(-3)}{(t-1)^4}\\\\M''_{X}(0)=\frac{(-2)(-3)}{(0-1)^4}= \frac{6}{(-1)^4}= \frac{6}{1}=6\\\\M''_{X}(t)=\frac{(-2)(-3)}{(t-1)^4}\\\\M''_{X}(0)=\frac{(-2)(-3)}{(0-1)^4}= \frac{6}{(-1)^4}= \frac{6}{1}=6\\\\M'''_{X}(t)=\frac{(-2)(-3)(-4)}{(t-1)^5}\\\\M''_{X}(0)=\frac{(-2)(-3)(-4)}{(0-1)^5}= \frac{24}{(-1)^5}= \frac{24}{-1}=-24\\\\\therefore \\\\M^{K}_{X} (t)=\frac{(-2)(-3)(-4).....(k+1)}{(t-1)^{k+2}}\\\\

M^{K}_{X} (0)=\frac{(-2)(-3)(-4).....(k+1)}{(-1)^{k+2}}\\\\\therefore\\\\E(X^n) = \frac{(-2)(-3)(-4).....(n+1)}{(-1)^{n+2}}\\\\

7 0
2 years ago
Explain why the equation 4x + 5 = 4x - 1 has no solutions.
expeople1 [14]

4x + 5 = 4x - 1


Move all terms containing

x to the left side of the equation.


4x-4x+5=-1


Subtract 4x-4x =0


0+5= 1


5= -1


Since −1≠5, there are no solutions.No solution



7 0
3 years ago
Read 2 more answers
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