Answer:
Yes
Step-by-step explanation:
Both quadrilaterals have two triangles. The triangles that coordinate with the triangles in the other quadrilateral are proven congruent by AAS and AA. That makes the quadrilaterals congruent.
Answer:
here you go
Step-by-step explanation:
1 is = 2 is >
The area of the resulting figure will be given by:
∫f(x)dx
f(x)=13/2x^3
thus
∫f(x)dx=13/2∫x³dx=13/8[x^4]
integrating over the inerval
13/8(12^4)-13/8(5^4)
=32680+3/8 sq. units
=
![y=x^2\\\\for\ x=\pm2\to y=(\pm2)^2=4\to(-2;\ 4);\ (2;\ 4)\\\\for\ x=\pm1\to y=(\pm1)^2=1\to (-1;\ 1);\ (1;\ 1)\\\\for\ x=0\to y=0^2=0\to (0;\ 0)](https://tex.z-dn.net/?f=y%3Dx%5E2%5C%5C%5C%5Cfor%5C%20x%3D%5Cpm2%5Cto%20y%3D%28%5Cpm2%29%5E2%3D4%5Cto%28-2%3B%5C%204%29%3B%5C%20%282%3B%5C%204%29%5C%5C%5C%5Cfor%5C%20x%3D%5Cpm1%5Cto%20y%3D%28%5Cpm1%29%5E2%3D1%5Cto%20%28-1%3B%5C%201%29%3B%5C%20%281%3B%5C%201%29%5C%5C%5C%5Cfor%5C%20x%3D0%5Cto%20y%3D0%5E2%3D0%5Cto%20%280%3B%5C%200%29)
Shift the graph of the function y = x², 5 units down /look at the picture #1/.
/look at the picture #2/ - your answer
Answer:
115
idk how to explain this but u just use the protractor