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rosijanka [135]
3 years ago
13

An anchor line for a tower needs to be replaced the tower is 96ft tall. the anchor line is 105ft long. how far from the tower ca

n it be placed, to the from the nearest tenth
a). 142.3ft
b). 42.5ft
c). 9ft
d). 60 ft​
Mathematics
1 answer:
likoan [24]3 years ago
4 0

Answer: 42.5ft

Step-by-step explanation: The wording in your question is a little unclear. I assume that you are looking for how far the anchor line is from the base of the tower.

If so, you can use the Pythagorean Theorem.

a^2 + b^ = c^2

96^ + b^2 = 105^2

Solve for b, gives you about 42.53ft round up and it is 42.5 ft :)

Happy to help

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Example:

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Cube with sides: 6. V= 6x6x6=?

How many times bigger is the second answer? That’s it!


Step-by-step explanation:


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Step-by-step explanation:

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You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o
Aleksandr [31]

Answer:

Therefore the circumference of the circle is =\frac{20\pi}{4+\pi}

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

\Rightarrow s=\frac{10-\pi r}{2}

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

A=\pi r^2+ (\frac{10-\pi r}{2})^2

\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2

\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}

\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25

For maximum or minimum \frac{dA}{dr}=0

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\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi

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\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}    > 0

For maximum or minimum

\frac{dA}{dr}=0

\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0

\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}

\Rightarrow r=\frac{10}{4+\pi}

\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0

Therefore at r=\frac{10}{4+\pi}  , A is minimum.

Therefore the circumference of the circle is

=2 \pi \frac{10}{4+\pi}

=\frac{20\pi}{4+\pi}

4 0
3 years ago
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