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Alex Ar [27]
3 years ago
13

Determine if the function is even, odd, or neither.

Mathematics
2 answers:
makkiz [27]3 years ago
6 0

Answer:

Even

Step-by-step explanation:

I think that it's even because the graph is reapeted, if it's odd, it's going to be like x^3

try it on desmos

stich3 [128]3 years ago
6 0
Even the ends of the waves are heading the same direction(up) if its odd one will be(one up and one down) even(both up/both down)
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State the Limits Rule and explain what it means
Evgen [1.6K]

Answer:

The limit of a sum is equal to the sum of the limits.

Step-by-step explanation:

The limits of a constant times a function is equal to the constant times the limit of the function.

4 0
3 years ago
Give the equation for a circle with the given center and radius.Center at (-10, -4), radius = 5A. (x−10)^2+(y−4)^2=25B. (x−4)^2+
BaLLatris [955]

D)(x+10)^2+(y+4)^2=5^2=25

Explanation

Step 1

We know that the general equation for a circle is

\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\  \end{gathered}

where

(h,k) is the center of the circel

and r is the radius

then, all we need to do is replace

Let

\begin{gathered} \text{center}\Rightarrow(h,k)\Rightarrow(-10,-4) \\ \text{radius}\Rightarrow r\Rightarrow5 \end{gathered}

replace the values

\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ (x-(-10))^2+(y-(-4))^2=5^2 \\ (x+10)^2+(y+4)^2=5^2=25 \end{gathered}

therefore, the answer is

D)(x+10)^2+(y+4)^2=5^2=25

I hope this helps you

7 0
1 year ago
I need help with this problem.
liberstina [14]
4050 divided by 3 = 1350
There is 4050 people in an arena and there is 3 sections of seats. How many people are in one section of seats?
6 0
3 years ago
WHAT IS 1+1 <br><br><br> If u get it right tell me;) good luck
ella [17]

Answer:

4

Step-by-step explanation:

;)

4 0
3 years ago
Read 2 more answers
Find the following rates. Round your answer to the nearest hundredth. a. ? % of 75 = 5 b. ? % of 28 = 140 c. ? % of 100 = 40 d.
Nimfa-mama [501]
A.15 b.500 c.40 d.7.5 yeah, not to confident but I think it's correct.
5 0
3 years ago
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