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tino4ka555 [31]
3 years ago
13

If b = 7 and A = 80 degrees, find c.

Mathematics
1 answer:
bixtya [17]3 years ago
6 0

Answer:

Step-by-step explanation:

7/sin10=c

c=40.31

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Pemdas, thank you! <br>(-8 × -6) -4² ​
Aleksandr-060686 [28]

Answer:

32

Step-by-step explanation:

(-8 × -6) - 4² ​

48 - 4²

48 - 16 = 32

P - Parentheses

E - Exponents

M - Multiplication

D - Division

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8 0
2 years ago
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Does anyone know the answer?<br> * ANSWER ASAP *
blsea [12.9K]
The correct answer is c
8 0
3 years ago
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The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi
Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Now, z_{critical} \text{ at 0.05 level of significance for one tail} = 1.64

Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

6 0
3 years ago
-2 (4t-3)+6t=5t-2 solve
ElenaW [278]
-8t+6+6t=5t-2
-2t+6=5t-2
-2t-5t=-2-6
-7t=-8
-7 -7
T=1.14 or 1 1/7
8 0
3 years ago
An airplane flew a distance of 650 km at an average speed of 300 km/h. How much time did the flight take
galina1969 [7]
650/300 = 2(1/6)
(1/6) of 1 hour = 10mins
The flight took 2hr and 10mins.
6 0
3 years ago
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