Consider
.
Given:
![\Delta AOB\cong \Delta BDC, AO=5\ m,BD=10\ m, AB=5\ m.](https://tex.z-dn.net/?f=%5CDelta%20AOB%5Ccong%20%5CDelta%20BDC%2C%20AO%3D5%5C%20m%2CBD%3D10%5C%20m%2C%20AB%3D5%5C%20m.)
To find:
The length of BC.
Solution:
We have,
![\Delta AOB\cong \Delta BDC](https://tex.z-dn.net/?f=%5CDelta%20AOB%5Ccong%20%5CDelta%20BDC)
We know that the corresponding parts of congruent triangles are congruent (CPCTC).
(CPCTC)
![5\ m=BC](https://tex.z-dn.net/?f=5%5C%20m%3DBC)
The length of BC is 5 m. Therefore, the correct option is A.
Let a and b represent the heights of the corresponding buildings (in meters).
... a = b +271 . . . . . . . a is 271 meters taller than b
... 2b -a = 211 . . . . . . if a is subtracted from twice b, the result is 211
Use the expression for a in the first equation to substitute for a in the second.
... 2b - (b+271) = 211
... b = 482 . . . . . . . . . . . simplify and add 271
... a = b +271 = 753
Building a is 753 meters tall; building b is 482 meters tall.
For this case, the first thing to do is to observe that the figure is symmetrical with respect to the FH axis.
Therefore, the following lengths are the same:
![GH = HK](https://tex.z-dn.net/?f=%20GH%20%3D%20HK%20%20)
So, by equalizing both sides we have:
![5m + 1 = 3m + 7](https://tex.z-dn.net/?f=%205m%20%2B%201%20%3D%203m%20%2B%207%20%20)
From here, we clear the value of m.
We have then:
![5m - 3m = 7 - 1\\2m = 6](https://tex.z-dn.net/?f=%205m%20-%203m%20%3D%207%20-%201%5C%5C2m%20%3D%206%20%20)
![m = \frac{6}{2}\\m = 3](https://tex.z-dn.net/?f=%20m%20%3D%20%5Cfrac%7B6%7D%7B2%7D%5C%5Cm%20%3D%203%20%20%20)
Answer:
The value of m is given by:
![m = 3](https://tex.z-dn.net/?f=%20m%20%3D%203%20)
Hey there!
The opposite of the square root of 25 is -5, and this is an <u>integer and a rational number and a real number.</u>
<u></u>
Hope it helps and have a great day!
I would say Jupiter but i may be wrong