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GalinKa [24]
3 years ago
11

?????????????????????????????

Mathematics
1 answer:
sergeinik [125]3 years ago
4 0

Answer:

B. 3

Step-by-step explanation:

If you were to multiply the top equation by 3 then the x value for the first equation would be 6 and since the bottom equation's x value is -6, if you were to add them, they would cancel eachother off.

LOL hope this makes sense :) Please give brainliest!! Thanks!!

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Write x2 - 8x + 13 = 0 in the form (x - a)2 = b, where a and b are integers. a.)(x - 4)2 = 3 b.) (x - 3)2 = 2 c.)(x - 2)2 = 1 d.
loris [4]
The answer is <span>a.)(x - 4)2 = 3.

(x - a)</span>² = b can be expressed as:
x² - 2ax + a² = b                                 ⇒ x² - 2ax + a² - b = 0

Our equation is                x² - 8x + 13 = 0.
The general formula is    x² - 2ax + (a² - b) = 0

Thus:
8x = 2ax    and a² - b = 13

Divide both sides of the first equation (8x = 2ax) by x:
8 = 2a           ⇒ a = 8 ÷ 2 = 4

Replace a in the second equation (a² - b = 13):
4² - b = 13     ⇒ b = 4² - 13 = 16 - 13 = 3

Now when we have a and b, let's just replace them in the general equation:
(x - a)² = b
(x - 4)² = 3
4 0
3 years ago
2. What is the vertex of the following parabola? *
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Answer:

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Step-by-step explanation:

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10. Each day, Valerie charges her lunch
Tomtit [17]
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What is the solution to the equation
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Find the area of the surface generated by revolving the curve x=\frac{y^3}{2} from 0 \leq y \leq 3 about the y-axis.
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In this problem:

dy/dx = 3x²/4

The surface area generated by revolving the curve y = x^3/4 on the interval [0,1] about the x-axis:

= 2π*∫(x^3/4)*√(1 + 9x^4/16) dx from 0 to 1

= π/8*∫x^3*√(16 +9x^4) dx from 0 to 1

u = 16 + 9x^4

du/36 = x^3 dx

= π/288*∫√u du from 16 to 25

= π/288[2/3*u^(3/2) eval. from 16 to 25]

= π/288[250/3 - 128/3]

= π/288[122/3] = 61π/432 </span>
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