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2 years ago

7

A company sells running shoes . If the price of a pair of shoes In dollars is p, the company estimates that it will sell 50, 000

- 400p pairs of shoes. Write an equation that represents the revenue dollars from selling running shoes if a pair of shoes is priced p at dollars .

1 answer:

swat322 years ago

5 0

Evet canım çok teşekkür ederim canım çok teşekkür ederiz çok güzel olmuş çok teşekkür ederim öğretmenim merhaba hocam nasılsınız hocam proje konularını atabilirmisiniz ne kadar çok seviyorum çok öpüyorum iyi

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Find an equation of the line containing the given pair of points (5,2) and (-3,5)

anzhelika [568]

(5,2)(-3,5)
slope = (5 - 2) / (-3 - 5) = -3/8

y = mx + b
slope(m) = -3/8
use either of ur points...(5,2)...x = 5 and y = 2
now we sub and find b, the y int
2 = -3/8(5) + b
2 = - 15/8 + b
2 + 15/8 = b
16/8 + 15/8 = b
31/8 = b

so ur equation is : y = -3/8x + 31/8....or 3x + 8y = 31

3 0

2 years ago

Consider the line y=-1/2x+8

OverLord2011 [107]

Given parameters:

Equation of the line is y = - $\frac{1}{2} x$ + 8

Unknown:

Slope of line parallel to this line = ?

Slope of line perpendicular = ?

Solution:

A line parallel to this line will have the same slope with it.

A line perpendicular will have the negative inverse of this slope;

Slope of line = - $\frac{1}{2}$

Slope of line parallel to this line = $-\frac{1}{2}$

Slope of line perpendicular = negative inverse = -( -( $\frac{1}{\frac{1}{2} }$ )) = 2

So, the slope of line parallel to this line is - 1/2 and that perpendicular is 2

6 0

2 years ago

The expression 3x^3-5x^2+3x-1 has ___ terms and a constant of ____.

Andrews [41]

<span>The expression 3x^3-5x^2+3x-1 has ___ terms and a constant of ____.
have four terms and 1 constant
</span>

5 0

3 years ago

In 30 minutes, a television station plays 8.5 minutes of commercials. The equation m + 8.5= 30 gives the length m in minutes of

zubka84 [21]

The solution to the equation would be 21.5

Why?

If you do the equation backwards

30 - 8.5 = x

You would get 21.5
You can plug it into the first equation to check!

:)

8 0

3 years ago

Read 2 more answers

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .

Subtract $-12x^2 -36x$ from both sides of the equation:

$38x + 7 = c(x + 3)$ .

By the same logic, $c = 38$ .

Hence the quotient would be $(4x^2 - 12x + 38)$ .

6 0

3 years ago