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Julli [10]
3 years ago
12

Suppose a basketball team had a season of games with the following characteristics: Of all the games, 60% were at-home games. De

note this by H (the remaining were away games). Of all the games, 25% were wins. Denote this by W (the remaining were losses). Of all the games, 20% were at-home wins. Of the at-home games, we are interested in finding what proportion were wins. Which of the following probabilities do you need to find in order to determine the proportion of at-home games that were wins?A. P(H)B. P(W)C. P(H and W)D. P(H | W)E. P(W | H)
Mathematics
1 answer:
Sedaia [141]3 years ago
6 0

Answer:

E. P(W | H)

Step-by-step explanation:

What each of these probabilities mean:

P(H): Probability of the game being at home

P(W): Probability of the game being a win.

P(H and W): Probability of the game being at home and being a win.

P(H|W): Probability of a win being at home.

P(W|H): Probability of winning a home game.

Which of the following probabilities do you need to find in order to determine the proportion of at-home games that were wins?

This is the probability of winning a home game. So the answer is:

E. P(W | H)

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3. y = -2x - 4<br> Slope = -2<br> y-intercept = _
baherus [9]

Answer:

0

Step-by-step explanation:

You first multiply -2(-2) which will be 4 since a negative times a negative is a positive. Next you subtract 4 and -4 which is 0. Lastly you bring down the y which is equal to 0.  

3 0
3 years ago
Please help
Nana76 [90]

Answer:

it looks like its negative 2

5 0
3 years ago
Read 2 more answers
D) x + y = 42 X-6 = 5 (-6)​
vovangra [49]

Answer: X = -24 Y = 66

Step-by-step explanation:

5(-6) = -30

X = 6 - 30 = -24

Y = 42 + 24 = 66

3 0
2 years ago
Read 2 more answers
How do I set up the equation for this word problem? A takes 1/2 of the diamonds plus 1 from the table. B takes 2/3 of what remai
nalin [4]

The first thief takes (1/2 x + 1) .  What remains ?   x - (1/2x + 1)

So the 2nd thief takes  2/3 of  [  x - (1/2x + 1) ]

   What remains ?    x - 2/3 [ x - (1/2x + 1) ]

So the 3rd thief takes    2/3 of  { x - 2/3 [ x - (1/2x + 1) ] }  and he takes 1 more .

   What remains ?    x - ( 2/3 { x - 2/3 [ x - (1/2x + 1) ] } + 1 )

And that whole ugly thing is equal to ' 1 ', so you can solve it for 'x'..

The whole problem from here on is an exercise in simplifying
an expression with a bunch of 'nested' parentheses in it.  
===============================================
This is a lot harder than just solving the problem with logic and
waving your hands in the air.  Here's how you would do that:

Start from the end and work backwards:

-- One diamond is left.
-- Before the 3rd thief took 1 more, there were 2.
-- That was 1/3 of what was there before the 3rd man took 2/3.
So he found 6 when he arrived.
-- 6 was 1/3 of what was there before the second thief helped himself.
So there were 18 when the 2nd man arrived.
-- 18 was 1 less than what was there before the first thief took 1 extra.
So he took his 1 extra from 19.
-- 19 was the remaining after the first man took 1/2 of all on the table.
So there were 38 on the table when he arrived.

Thank you for your generous 5 points.


 
3 0
3 years ago
Suppose P(E) = 81%; P(E and F) = 9%; and P(E or F) = 65%,
PIT_PIT [208]

Using Venn probabilities, it is found that P(F) = -0.07, which is not a probability, as it is a negative value.

------------------

  • We have two events, E and F.
  • Their probabilities are: P(E) = 0.81, P(E \cap F) = 0.09, P(E \cup F) = 0.65
  • The probabilities are related by the following equation:

P(E \cap F) = P(E) + P(F) - P(E \cup F)

  • Replacing into the equation, we can find P(F).

0.09 = 0.81 + P(F) - 0.65

0.16 + P(F) = 0.09

P(F) = -0.07

P(F) = -0.07, which is not a probability, as it is a negative value.

A similar problem is given at brainly.com/question/21421475

4 0
3 years ago
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