Question

Suppose a basketball team had a season of games with the following characteristics: Of all the games, 60% were at-home games. Denote this by H (the remaining were away games). Of all the games, 25% were wins. Denote this by W (the remaining were losses). Of all the games, 20% were at-home wins. Of the at-home games, we are interested in finding what proportion were wins. Which of the following probabilities do you need to find in order to determine the proportion of at-home games that were wins?A. P(H)B. P(W)C. P(H and W)D. P(H | W)E. P(W | H)

Answer 1

Answer:

E. P(W | H)

Step-by-step explanation:

What each of these probabilities mean:

P(H): Probability of the game being at home

P(W): Probability of the game being a win.

P(H and W): Probability of the game being at home and being a win.

P(H|W): Probability of a win being at home.

P(W|H): Probability of winning a home game.

Which of the following probabilities do you need to find in order to determine the proportion of at-home games that were wins?

This is the probability of winning a home game. So the answer is:

E. P(W | H)