<u>Solution</u><u>:</u>
![\sqrt{4x + 13} = x + 2](https://tex.z-dn.net/?f=%20%5Csqrt%7B4x%20%2B%2013%7D%20%20%3D%20x%20%2B%202)
![= > ( \sqrt{4x + 13} ) ^{2} = (x + 2) ^{2}](https://tex.z-dn.net/?f=%20%3D%20%20%3E%20%28%20%5Csqrt%7B4x%20%2B%2013%7D%20%29%20%5E%7B2%7D%20%20%3D%20%28x%20%2B%202%29%20%5E%7B2%7D%20)
- Now, square root and square gets cancel out in the LHS. And in the RHS, apply the identity: (a + b)² = a² + 2ab + b².
![= > 4x + 13 = {(x)}^{2} + 2 \times x \times 2 + (2) ^{2} \\ = > 4x + 13 = {x}^{2} + 4x + 4](https://tex.z-dn.net/?f=%20%3D%20%20%3E%204x%20%2B%2013%20%3D%20%20%7B%28x%29%7D%5E%7B2%7D%20%20%2B%202%20%5Ctimes%20x%20%5Ctimes%202%20%2B%20%282%29%20%5E%7B2%7D%20%5C%5C%20%20%3D%20%20%3E%204x%20%2B%2013%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%20%2B%204x%20%2B%204)
- Now, transpose 4x and 4 to LHS.
![= > 4x - 4x + 13 - 4 = {x}^{2} \\](https://tex.z-dn.net/?f=%20%3D%20%20%3E%204x%20-%204x%20%2B%2013%20-%204%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%5C%5C%20)
- Now, do the addition and subtraction.
![= > {x}^{2} = 9 \\ = > x = \sqrt{9} \\ = > x = ±3](https://tex.z-dn.net/?f=%20%3D%20%20%3E%20%20%7Bx%7D%5E%7B2%7D%20%20%3D%209%20%5C%5C%20%20%3D%20%20%3E%20%20x%20%3D%20%20%5Csqrt%7B9%7D%20%20%5C%5C%20%20%3D%20%20%3E%20x%20%3D%20%C2%B13)
<u>Answer</u><u>:</u>
<u>x </u><u>=</u><u> </u><u>±</u><u> </u><u>3</u>
Hope you could understand.
If you have any query, feel free to ask.
Answer:
About 40% of students own a cat
Step-by-step explanation:
Answer:
17.6
Step-by-step explanation:
Answer:
x = notebooks
y = indexboks
3x+4y=32 ( here is spent all money so I add 32 here )
5x+5y=50
by elemination method
3x+4y=32×5
5x+5y=50×4 ( here I'm going to eliminate y )
15 x+20y= 160
20x+20y= 200
- - = -
____________
-5x = -40
x = - 40 / -5
x = 8
here - × - = + so iam taking positive 8
now substitute the value of x in any equation
3×8+4y = 32
24 + 4y = 32
4y = 32-24
y = 8 / 4
y = 2
CHECKING
SUBSTITUTE BOTH VALUES IN ANY EQUATION
5×8+5×2 = 50
40 + 10 = 50
50 = 50
I SUBSTITUTE IN 2ND EQUATION