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Ivenika [448]
3 years ago
15

I need help with number 2.

Mathematics
1 answer:
Lisa [10]3 years ago
5 0

Answer:

(1)

Step-by-step explanation:

Given

\frac{2x}{a} + b = c ( subtract b from both sides )

\frac{2x}{a} = c - b ( multiply both sides by a to clear the fraction )

2x = a(c - b) ← distribute

2x = ac - ab ( divide both sides by 2 )

x = \frac{ac-ab}{2} → (1)

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The surface area of the cone is 43.75pie cm^2. What is the slant height of the cone and the diameter is 5
Masteriza [31]
If the diameter of the cone is 5, then the radius of it will be half that, or 2.5, thus

\bf \textit{total surface area of a cone}\\\\
SA=\pi r\stackrel{slant~height}{\sqrt{r^2+h^2}}+\pi r^2~~
\begin{cases}
r=radius\\
h=height\\
------\\
SA=43.75\pi \\
r=2.5
\end{cases}
\\\\\\
43.75\pi =\pi (2.5)\sqrt{r^2+h^2}+\pi (2.5)^2
\\\\\\
43.75\pi -\pi (2.5)^2=2.5\pi \sqrt{r^2+h^2}
\\\\\\
43.75\pi -6.25\pi =2.5\pi \sqrt{r^2+h^2}\implies 37.5\pi =2.5\pi \sqrt{r^2+h^2}
\\\\\\
\cfrac{37.5\pi }{2.5\pi }=\sqrt{r^2+h^2}\implies 15=\sqrt{r^2+h^2}
3 0
4 years ago
What's the answer ?<br><br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B245%20%2B%2044%7D%20" id="TexFormula1" title=" \sq
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\huge\mathfrak\pink{Answer...}

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Dennis_Churaev [7]
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3 years ago
What is the surface area of a cone with a height of 15 and the diameter of 12?
V125BC [204]

Answer:

417.62

A=πr(r+\sqrt{x} h2+r2)Step-by-step explanation:

because radius is half of diameter and then you would use this equation to solve

6 0
4 years ago
In a recent Super Bowl, a TV network predicted that 53 % of the audience would express an interest in seeing one of its forthcom
rjkz [21]
<h3>Answer: -0.196</h3>

======================================================

Explanation:

We're conducting a one proportion Z test.

The hypothesized population proportion is p = 0.53, which is not to be confused with the p-value (unfortunately statistics textbooks seem to overuse the letter 'p'). Luckily this problem is not asking for the p-value.

The sample population proportion is

phat = x/n = 41/79 = 0.518987 approximately

The standard error (SE) is

SE = sqrt(p*(1-p)/n)

SE = sqrt(0.53*(1-0.53)/79)

SE = 0.056153 approximately

Making the test statistic to be

z = (phat - p)/(SE)

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z = -0.19612487311452

z = -0.196

Which is approximate and rounded to 3 decimal places.

3 0
4 years ago
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