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2 years ago

I need help with number 2.

Mathematics

1 answer:

Lisa [10]2 years ago

5 0

Answer:

(1)

Step-by-step explanation:

Given

$\frac{2x}{a}$ + b = c ( subtract b from both sides )

$\frac{2x}{a}$ = c - b ( multiply both sides by a to clear the fraction )

2x = a(c - b) ← distribute

2x = ac - ab ( divide both sides by 2 )

x = $\frac{ac-ab}{2}$ → (1)

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Find each trig ratio

Elena L [17]

Answer:

Step-by-step explanation:

7 0

3 years ago

I rlly need help with this gr 11 math problem

prohojiy [21]

Answer:

a) $\frac{d-5.50}{0.45}$

b) The inverse function is a reflection of the original function across the line

y = x. For example, if the function f applied to an input x gives a result of y, then applying its inverse function g to y gives the result x. So you would use it to find the x-value at a y just like you use the original to find the y value at an x.

Step-by-step explanation:

To do an inverse of a function you first switch the independent variable (d) and the dependent variable (c).

d = 0.45c + 5.50

Then you solve for c

d - 5.50 = 0.45 c

c = (d-5.50)/0.45

8 0

3 years ago

What's bigger 80% or 1/8?

Kobotan [32]

An easy way to solve this is to convert 1/8 into a percentage then see from that point.

To turn 1/8 into a percentage, you must first get the decimal form of the fraction. In this case, 1/8 as a decimal is 0.125.

Now that we have the decimal form, we can divide the decimal over 100 (common numerical number to use when dividing) to get the percentage, which should be 12.5%.

Now, our new question is 'what's bigger, 80% or 12.5%?'

The answer is 80%, since it is larger than 12.5%.

4 0

3 years ago

Read 2 more answers

How do you write or break down this decimal:<br><br> 45.50 =

son4ous [18]

Step-by-step explanation:

45.50

Converting decimal

45.50 x 100 = 4550

4 0

3 years ago

Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator

SpyIntel [72]

$\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}$
$\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)$

When $x=3$ , you're left with

$147=49a_1\implies a_1=\dfrac{147}{49}=3$

When $x=\sqrt2$ or $x=-\sqrt2$ , you're left with

$\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}$

Adding the two equations together gives $-10=2a_5$ , or $a_5=-5$ . Subtracting them gives $2\sqrt2=2\sqrt2a_4$ , $a_4=1$ .

Now, you have

$5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)$
$5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)$
$2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)$

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that $a_2x^4=2x^4$ and $a_3(-3)(-2)=6a_3=-6$ . These alone tell you that you must have $a_2=2$ and $a_3=-1$ .

So the partial fraction decomposition is

$\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}$

7 0

3 years ago