3 years ago

Integral of of sin x/cosˆ2 x

Mathematics

1 answer:

marin [14]3 years ago

7 0

Answer:

$\sec x + c$

Step-by-step explanation:

$\int \frac{ \sin \: x}{ { \cos}^{2}x } \: dx \\ \\ = \int \frac{ \sin \: x}{ { \cos}x } . \frac{ 1}{ { \cos}x } \: dx \\ \\ = \int \tan x . \sec x \: dx \\ \\ = \sec x + c$

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Vadim26 [7]

Answer:

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Step-by-step explanation:

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4 years ago

Liz created this table to show the ratio of red pencils to green pencils in her box. Identify the ratios that are equivalent to

ratelena [41]

1/3 if you simplify them

4 0

3 years ago

Solve for t. d=−16t2+4t t=12±41−4d‾‾‾‾‾‾√ t=8±1−4d‾‾‾‾‾‾√ t=18±1−4d√8 t=12±41−4d√2

dangina [55]

Answer:

$t=\dfrac{1}{8}\left(1\pm\sqrt{1-4d}\right)$

Step-by-step explanation:

Rearranging your quadratic to standard form, you get ...

16t^2 -4t +d = 0

For the quadratic formula, you have ...

a = 16

b = -4

c = d

so the solution is ...

$t=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\t=\dfrac{-(-4)\pm\sqrt{(-4)^2-4(16)(d)}}{2(16)}=\dfrac{4\pm 4\sqrt{1-4d}}{32}\\\\t=\dfrac{1}{8}\left(1\pm\sqrt{1-4d}\right)$