Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
Answer:0
Step-by-step explanation:2≠8,10 so we use the bottom formula. We get 4 - 6 + 2=0
Sorry about my first answer then it would 20% because if you take 30 and divide 20% you'll get 6 so again sorry I was wrong 20 percent though is right.
Answer:
Step-by-step explanation:
A/4 = b/7 Cross multiply: 7a =4b Divide by b: (7a/b)=4 Multiply by 1/7: a/b =4/7
4/7 is your answer
